Unknown: final velocity, vf
Known:
initial velocity, vi = 0m/s
time, t = 15.0s
average acceleration, a = 2.40m/s2
Equation:
vf = vi + at
Solution:
vf = 0 + 2.40m/s2 x 15.0s = 36.0m/s
what is the change in speed or velocity? average acceleration will be change in speed or velocity divided by time taken (4 seconds in ur case)
If the acceleration was constant (15 + 25) /2 = 20 (time does not figure into the averaging at all!)
No starting velocity was given, so I can't give a correct answer, but I can answer part of the question. Given an acceleration and a time through which an object accelerates, you can determine the change in velocity. Acceleration is just the change of velocity over a period of time. Since we have an acceleration of -3.1 meters per second squared, acting for two seconds, we have a change in velocity of -6.2 meters per second. Take the original velocity and subtract 6.2 meters per second to get the answer.
Average acceleration = (change in speed) / (time for the change) = (88 - 44) / (11) = 4 meters per second2
Acceleration is a measure of the rate of change of velocity.Assume the question is, "A car accelerates from 25 kph to 55 kph in 30 sec what is its acceleration?The formula for this calculation is v = u + ft : v = final velocity, u = initial velocity, f = acceleration, t = time. But all measurements have to be in related units. As speed is measured in kph then time needs to be converted to hours. 30 seconds = 1/2 minute = 1/120 hour55 = 25 + f/120 : 30 = f/120 : f = 30 x 120 = 3600 kph2As there are 3600 seconds in 1 hour then the acceleration can be stated as 1 kps2.
what is the change in speed or velocity? average acceleration will be change in speed or velocity divided by time taken (4 seconds in ur case)
A car accelerates from a standstill to 60km/hr in 10.0 seconds what is its acceleration
the final velocity = initial velocity + acceleration x time; since acceleration is negative final velocity = 45 - 10x3 = 45 -30 = 15 mph
The answer will depend on its acceleration.
the acceleration of the car is 1.179m/s/s given the formula provided.
If the acceleration was constant (15 + 25) /2 = 20 (time does not figure into the averaging at all!)
No
Speed = (acceleration) x (time) = 9 x 8 = 72 ft/sec
-6.38715
No starting velocity was given, so I can't give a correct answer, but I can answer part of the question. Given an acceleration and a time through which an object accelerates, you can determine the change in velocity. Acceleration is just the change of velocity over a period of time. Since we have an acceleration of -3.1 meters per second squared, acting for two seconds, we have a change in velocity of -6.2 meters per second. Take the original velocity and subtract 6.2 meters per second to get the answer.
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
Yes, velocity is acceleration x time. If acceleration is the same, velocity can be different as it changes with time. For example a car accelerating with constant acceleration will have a different velocity after 5 seconds than it will have at 2 seconds.