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It depends on what the initial velocity was. If it was 0, then: 11-0 = 2.2 m/s squared 5
no, you need to know its initial velocity to determine this; if initial velocity is zero then distance is 1/2 acceleration x time squared
If you have an initial and final velocity and time you can figure it out with this equation, Vf squared=Vi squared1/2a(t squared) If you don't have those you cannot find acceleration. However the acceleration on Earth is a constant -9.81
Assuming constant acceleration: distance = v(0) t + (1/2) a t squared Where v(0) is the initial velocity.
aSsuming constant acceleration, and movement along a line, use the formula: vf2 = vi2 + (1/2)at2 (final speed squared equals initial speed squared plus one-half times acceleration times time squared).
Kinematics. Final velocity squared = initial velocity squared + 2(gravitational acceleration)(displacement)
It depends on what the initial velocity was. If it was 0, then: 11-0 = 2.2 m/s squared 5
Acceleration= distance / velocity squared
Linear Velocity = Initial Velocity (m/s) + Acceleration (m/s2) * t 43.2 km/h
It will depend upon the initial velocity of the body. If 'u' be the initial velocity of the body, then the final velocity will be: v = u + at (v = final velocity, a = acceleration, t = time) i.e., v=u+10*7 = (u + 70) m/sec. If u=0 (i.e the initial velocity be zero) then final velocity, v=70 m/sec.
no, you need to know its initial velocity to determine this; if initial velocity is zero then distance is 1/2 acceleration x time squared
If you have an initial and final velocity and time you can figure it out with this equation, Vf squared=Vi squared1/2a(t squared) If you don't have those you cannot find acceleration. However the acceleration on Earth is a constant -9.81
Velocity can be measured in metres per second, not metres per second squared. Acceleration is measured in metres per second squared but knowing only the acceleration does not help in finding the velocity.
v2 = u2+ 2as where v squares is the final velocity , u squared is the initial velocity , a is the acceleration and s is the distance travelled. If it is free fall take a = 10m/s squared ( as gravity ).
Assuming constant acceleration: distance = v(0) t + (1/2) a t squared Where v(0) is the initial velocity.
It is 0.1 metre per second-squared.
Speed, or velocity, is measured in distance per second; it is the rate of change of distance with time.Acceleration is the rate of change of velocity with time, or distance per second per second, which is distance per seconds squared,