The derivative of f(x) = x mod b is
f'(x)=1, except where x is a multiple of b, when it is undefined.
A linear function, for example y(x) = ax + b has the first derivative a.
Solve for when the first derivative is equal to zero. If you don't know how to take a derivative, then put the equation into the form y = Ax2 + Bx + C. The derivative of this will be 2Ax + B, so at x = -B / (2*A), and y = -B2/(4*A) + C
Yes.
The first derivative of ln x is 1/x, which (for the following) you better write as x-1.Now use the power rule:Second derivative (the derivative of the first derivative) is -1x-2, the third derivative is the derivative of this, or 2x-3. You may now wish to write this in the alternative form, as 2 / x3.
well, the second derivative is the derivative of the first derivative. so, the 2nd derivative of a function's indefinite integral is the derivative of the derivative of the function's indefinite integral. the derivative of a function's indefinite integral is the function, so the 2nd derivative of a function's indefinite integral is the derivative of the function.
A linear function, for example y(x) = ax + b has the first derivative a.
x/mo x
The first derivative is m and the second is 0 so the third is also 0.
Solve for when the first derivative is equal to zero. If you don't know how to take a derivative, then put the equation into the form y = Ax2 + Bx + C. The derivative of this will be 2Ax + B, so at x = -B / (2*A), and y = -B2/(4*A) + C
The derivative of e^u(x) with respect to x: [du/dx]*[e^u(x)]For a general exponential: b^x, can be rewritten as b^x = e^(x*ln(b))So derivative of b^x = derivative of e^u(x), where u(x) = x*ln(b).Derivative of x*ln(b) = ln(b). {remember b is just a constant, so ln(b) is a constant}So derivative of b^x = ln(b)*e^(x*ln(b))= ln(b) * b^x(from above)
The derivative of e^u(x) with respect to x: [du/dx]*[e^u(x)]For a general exponential: b^x, can be rewritten as b^x = e^(x*ln(b))So derivative of b^x = derivative of e^u(x), where u(x) = x*ln(b).Derivative of x*ln(b) = ln(b). {remember b is just a constant, so ln(b) is a constant}So derivative of b^x = ln(b)*e^(x*ln(b))= ln(b) * b^x(from above)
if a = b (mod m) and b = c (mod m) then a = c (mod m)
(a/b)'= (ba'-ab')/(b²)
mod(b - 4, 24)
All it means to take the second derivative is to take the derivative of a function twice. For example, say you start with the function y=x2+2x The first derivative would be 2x+2 But when you take the derivative the first derivative you get the second derivative which would be 2
Find the derivative of Y and then divide that by the derivative of A
Speed is scalar (it doesn't have direction), and the magnitude of velocity (a vector). The first derivative of velocity is acceleration, therefore the first derivative of speed is the magnitude of acceleration.