The numbers must be greater than (mean - 2*sd) and laess than (mean + 2*sd).
Multiply them as you would any two numbers. However, you should note that the standard deviation of a product of two variables is not the product of their standard deviations. That is, SD(XY) ≠SD(X)*SD(Y)
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pysics chemical r2a
It would be useful to know what the deviations were from.
There is no such formula; there are infinitely many number between them.
To find the average of n numbers, take the sum of the numbers and divide by n.
z-score or standard score... tells you how many standard deviations away from the mean a particular number is in relations to all numbers in a population (or sample)
It is: 630 by finding the prime factors of the given numbers
For different sets of data, the mean would be the summation of all observations, which are normally subdivided by the observation numbers. The mean value would frequently be quoted with standard deviations: mean would describe data central locations then standard deviations illustrate the spread. Substitute dispersion measures include mean variations that are always equal to average absolute deviations from the mean values. It is minimally responsive to the outliers. Hope this helps.
multiply the mean by the amount of numbers
ZeroDetails:The "Standard Deviation" for ungrouped data can be calculated in the following steps:all the deviations (differences) from the arithmetic mean of the set of numbers are squared;the arithmetic mean of these squares is then calculated;the square root of the mean is the standard deviationAccordingly,The arithmetic mean of set of data of equal values is the value.All the deviations will be zero and their squares will be zerosThe mean of squares is zeroThe square root of zero is zero which equals the standard deion
there is no formula, but to find the mode in a set of numbers, just look for the same number that appears the most. ex: 2,5,4,6,7,5,4,3,3,3,3.7,5,3,5,6,7,5,4. so the mode of this would be 3 because 3 is appearing the most in this set of numbers.