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What is the formula of the density of a steel ball in kgm3 which has a diameter of 7.5mm and a mass of 1.675g?
Wiki User
∙ 11y ago
Mass = 1.675 g = 1.675*10-3 kg.
Diameter = 7.5 mm => radius = 3.75 mm = 3.75*10-3 m
Volume = 4/3*pi*r3 = 2.209*10-7 m3
So density = Mass/vol = 1.675*10-3/(2.209*10-7) = 7.583*103 kg/m3 = 7583 kg/m3
Wiki User
∙ 11y ago
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