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The only way to determine the cable wire size needed for a 1000 watt air conditioner is to find the load size. To get the load size you will need to use the formula Amps = Watts or Volts. With that being said, you will need a number 14 copper wire.
120mm
The Full load current of that amp is approx. 17A, but you base you fuse size between the Full load current of your load and the current carrying capacity of the supply cable, if the size or the CCC of the cable is unknown, I would recommend sticking as close to the FLC as possible
Assuming being fed by c32 breaker for start load minimum cable size SWA is 70mm which will go to 456 meters
Volt Amps conversion
Yes I could. How?
There is no formula to calculate the length of a wire. The length of a wire is determined by the distance from the power source to where the load is situated.
for DC load and if its copper wire the cross section of the conductor wire is generally calculated as 1/4 th of the current rating . Eg for a DC load of 16 amp the copper conductor with 4 mm square is selected.
To answer this question the size of the cable or the amperage of the load is needed to calculate the correct wire size and connectors to fit the cable.
Mechanical advantage=load/effort
To calculate the formula for duct sizing divide the room load by the whole house load. Next multiply those results by the equipment CFM.
The length of the cable is determined by the distance from the center of the distribution panel to the center of the load.
There are various formula of load calculation. Power equals current multiplied by the voltage. Power can also be computed by multiplying the resistance by the square of the current.
Load cable generally means the final cable before the actual load. So on a clothes dryer the "Load Cable" would be the cable running from the outlet to the actual clothes dryer.
Load cable generally means the final cable before the actual load. So on a clothes dryer the "Load Cable" would be the cable running from the outlet to the actual clothes dryer.
If you know the size of the load to be served, multiply it by 125% ( times 1.25) and choose a conductor that is rated for that ampacity or higher.
Divide the heat loss or gain obtained by the load calculation by square footage of the building.