0.5 Hz (that is, 0.5 persecond)
Period = 1/78.6 seconds = 0.01272 seconds
Assuming that seconds refers to the period, the frequency is the reciprocal (1 / period in seconds). The height of the wave is irrelevant in this case.
Period = 1/FrequencySo if we set Frequency = x THEN:10 = 1/x10x = 1x = 1/10IF Period of a Wave is 10 Seconds THEN The Frequency =1/10 or .10
4 Hz
0.17 Hz
Period = 1/Frequency = 0.00175 seconds (approx)Period = 1/Frequency = 0.00175 seconds (approx)Period = 1/Frequency = 0.00175 seconds (approx)Period = 1/Frequency = 0.00175 seconds (approx)
Period = 1/78.6 seconds = 0.01272 seconds
Vibration is the frequency of the wave.
Assuming that seconds refers to the period, the frequency is the reciprocal (1 / period in seconds). The height of the wave is irrelevant in this case.
The frequency is the reciprocal of the period. In other words, divide 1 by the period. If the period is in seconds, the frequency is in hertz.
.05 seconds
0.004 seconds
Period = 1/FrequencySo if we set Frequency = x THEN:10 = 1/x10x = 1x = 1/10IF Period of a Wave is 10 Seconds THEN The Frequency =1/10 or .10
Period = (4 seconds) / (2 waves) = 2 seconds per wave Frequency = (2 waves) / (4 seconds) = 0.5 Hz.
depends on what type of vibration the vibrations that are counted in atomic closcks are multiple billions of times a second and the vibration of the earth or RESONATION is 6hertz im pretty shure and the vibration of the movement of the earth is one pulse every year a rediculusly long wavelength be more spesific
Frequency = 1/period = 1/0.25 = 4 Hz.
Period = 1 / frequency = 1/272 = 0.003676 second (rounded)