A polygon must have 3+ sides, so I'm not entirely sure what you mean.
circle
11
There is no such thing as a 2-sided polygon.
There is no such thing as a two-sided polygon.
The sum of the angles of a regular n-sided polygon is equal to (n - 2) x 180 degrees.Therefore, the sum of the angles of a regular 40-sided polygon (tetradecagon) is equal to (40 - 2) x 180 = 6840 degrees. Therefore, 6840 refers to the sum of the degrees, not the number of diagonals.The number of diagonals of an n-sided polygon is given by n(n-3)/2. So a 40-sided polygon has 40*37/2=740 diagonals.
The sum of the interior angles of a convex polygon with n sides is given by (n-2)x180o. So for a 40 sided polygon n=40; thus (40-2)x180o = 38x180o = 6840o.
Since a three sided polygon is another name for a triangle. We would use the formula of * (n - 2)180 = degrees of the polygon * n = number of sides of the polygon * (3(sides) - 2)180 * (1)180) * = 180o
A 4-sided polygon has 2 diagonals. A 5-sided polygon, 5. 6-sided, 9. By induction, an n-sided polygon has 'n*(n-3)/2' diagonals. "n" is how many sides a shape has. so, (7)*(7-3)/2 now we have, 7*4/2 so, 28/2 = 14 Therefore, a 7-sided polygon would have 14 diagonals.
Use this form to work out the problem: (n - 2)180° where n is the number of sides Suppose that we have a regular polygon. This is the example of a convex polygon. Given that we have a 5-sided convex polygon, we obtain: (5 - 2)180° = 3 * 180° = 540°
There cannot be any such thing. I think it's a right angle
There aren't two sided polygons