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The sum of the angles of a regular n-sided polygon is equal to (n - 2) x 180 degrees.
Therefore, the sum of the angles of a regular 40-sided polygon (tetradecagon) is equal to (40 - 2) x 180 = 6840 degrees. Therefore, 6840 refers to the sum of the degrees, not the number of diagonals.
The number of diagonals of an n-sided polygon is given by n(n-3)/2. So a 40-sided polygon has 40*37/2=740 diagonals.
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What is the sum of interior angles of a 40 sided polygon?
180*(40-2) = 180*38 = 6840 degrees.
How many sides does a polygon have when the interior angles add up to 6840?
There are: (6840+360)/180 = 40 sides
How many diagonals will a 40 sided polygon have?
740 The number of digaonals is given by n(n-3)/2, where n is the number of sides (or vertices) of a polygon: 40(40-3)/2=20*37=740 For a proof, see: http://www.artofproblemsolving.com/Wiki/index.php/Diagonal
What do you call a 40 sided polygon?
tetracontahedron
What is a forty sided polygon called?
40-gon.
What is the interior of a 40 side polygon?
The interior angles of a 40 sided polygon add up to 6840 degrees
What is the sum of interior angles of a 40 sided polygon?
180*(40-2) = 180*38 = 6840 degrees.
How many diagonals are there in a 40-sided polygon?
0.5*(402-120) = 740 diagonals
How many diagonals does a 44 sided polygon has?
It has 40 diagonals.Improved Answer:-Using the formula for diagonals of a polygon: 0.5*(442-132) = 902 diagonals
How many sides does a polygon have when the interior angles add up to 6840?
There are: (6840+360)/180 = 40 sides
What is a 40 sided polygon?
The name of a 40 sided polygon is Tetracontagon.
What is the number of sides of a regular polygon if one angle measures 171 degrees?
The formula to find the sum of the angles of a polygon is: 180(n - 2) Since we know that one angle of this regular polygon is 171 degrees, we can find what kind of polygon it will be, using the formula: 180(n - 2) = 171n 180n - 360 = 171n 180n - 171n = 360 9n = 360 n = 360/9 n = 40 Thus the polygon is a 40-sided polygon. Check: 180(40 - 2) = 180(38) = 6840, which is the sum of the angles of the polygon. 6840/40 = 171 degrees, which is the measure of one of the angles of that polygon .
How many sides a 40 sided polygon have?
A 40-sided polygon has 40 sides. Count again, to be sure.
What are the sum of the interior angles of a polygon with 40 sides?
The sum of the interior angles of a polygon can be calculated using the formula: [ \text{Sum of interior angles} = (n - 2) \times 180^\circ ] where (n) is the number of sides of the polygon. For a polygon with 40 sides ((n = 40)): [ \text{Sum of interior angles} = (40 - 2) \times 180^\circ = 38 \times 180^\circ = 6840^\circ ] Thus, the sum of the interior angles of a polygon with 40 sides is **6840 degrees Read more....tinyurl com/22enuvst
How many sides on a polygon with the sum of the interior angles is 6840?
If the polygon has n sides, the sum of the interior angles is (n - 2)*180 degrees. So (n - 2)*180 = 6840 (n - 2) = 6840/180 = 38 So n = 38 + 2 = 40 sides.
How many diagonals will a 40 sided polygon have?
740 The number of digaonals is given by n(n-3)/2, where n is the number of sides (or vertices) of a polygon: 40(40-3)/2=20*37=740 For a proof, see: http://www.artofproblemsolving.com/Wiki/index.php/Diagonal
What do you call a 40 sided polygon?
tetracontahedron
