It is a horizontal line 5 units above the x-axis.
That line is horizontal on the graph. Its slope is zero.
The figures are exactly the same, but every point on the first graph is exactly 13 below the corresponding point on the second one.
The equation y = 4x^2 + 5 is a parabola
If: y = -2 and y = 2/5x-4 Then: x = 5 The lines meet at: (5, -2)
-5
y= -5
-5
5
No.
That line is horizontal on the graph. Its slope is zero.
17
y - 2 = 5 is the same as y = 7, which is a horizontal line above the x-axis at y=7.
No translation will invert a quadratic graph.
The figures are exactly the same, but every point on the first graph is exactly 13 below the corresponding point on the second one.
x + y = 5y = -x + 5The graph is a straight line, with [ slope = -1 ], passing through the point [ y = 5 ] on the y-axis.
The equation y = 4x^2 + 5 is a parabola
If: y = -2 and y = 2/5x-4 Then: x = 5 The lines meet at: (5, -2)