(1) 5x+y=-12 (2) 7x-3y=-30 From (1) one gets y = -12-5x Put into (2) 7x-3y = 7x -3 (-12-5x) = 7x + 36 +15 x = 22x +36=-30 22x = -30-36 = -66 so x = -3 and y=-12-5x = -12-5x-3= 3 The solution is (-3,3)
5(-2)+(-3)(-4) =-(10)+12 =2
First get y in terms of x: 5x-2y=-12 ----- -2y=-12-5x ------ y=6+(5/2)x Sub into other equation: 2x+3y=-1 ---- 2x+3(6+(5/2)x)=-1 Solving for x gets: x= -2 Sub into other equation: 5x-2y= -12 --- 5(-2)-2y= -12 --- y=1 So x= -2, and y= 1
27 + y = 42 - 4y so 5y = 15 making y = 3 and x = 6
First, reflect the graph of y = x² in the x-axis (line y = 0) to obtain the graph of y = -x²; then second, shift it 3 units up to obtain the graph of y = -x² + 3.
12
y = 2x + 5x - 12 = 7x - 12 So the zero is 12/7 = 1.7143 (approx)
-9
y = 5x + 2
y=-5x+8 the slope is -5.
To work out y=-5x-10 you can plot a graph.
17
x=6 y=30
-5
y = 2x -1 y = 5x -13 So: 5x -13 = 2x -1 5x -2x = 13 -1 3x = 12 x = 4 and by substituting y = 7
17
The graphs of y = 5x - 2 and y = x - 2 will have different slopes but with the same y intercepts.