y - 2 = 5 is the same as
y = 7, which is a horizontal line above the x-axis at y=7.
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Given: x2 + y2 - 10x + 4y + 4 = 0 First, we'll move our constants to the right: x2 + y2 - 10x + 4y = -4 Then group terms with the same variables together: x2 - 10x + y2 + 4y = -4 Then complete the squares: x2 - 10x + 25 + y2 + 4y + 4 = -4 + 25 + 4 (x - 5)2 + (y + 2)2 = 25 And there we have it. This is an equation for a circle whose center point is at (5, -2), with a radius of √25, which equals 5.
When y=4, x=8/5
hey,the graph of x=5 is a straight line parallel to Y-axis. all the points on the line have x-coordinate equal to 5. so on the X-axis just draw a perpendicular line 5 units away.
-2x=2y+5 +2x -2y -2y=2x+5 /-2 y=-1/1+2.5
5, of course!