' -6 ' and ' 6 ' are not points. On a 2-dimensional (flat) graph, you need two coordinates
to locate one point.
(On a 3-dimensional (solid) graph, you need three coordinates to locate one point.
And there's no such thing as a 1-dimensional graph.)
negative one and a half
the graph of y = |x| (absolute value of x) looks like a V with the point of the V at the origin. When x is negative (left half of graph), the line y = -x coincides with |x| so this half has a slope of -1. When x is positive (right half of graph), the line y = x coincides with |x| so this half has a slope of +1.
The graph of that function looks like a big letter ' V '. The point of the 'V' is at the origin,the left half has slope = -3, and the right half has slope = 3.
Since distance is 1/2 at^2 where a is acceleration, it represents one half of the acceleration
That's unusual. I guess your teacher is trying to make you think a bit. It's a good mental exercise, though. You may recall that the units of acceleration are meters per second squared. That gives you a clue right there. And if you knew Calculus, you'd know that acceleration is the second derivative of distance, s, with respect to time, t: d2s/dt2. So, by now you're probably getting the feeling that the slope of a distance-time squared graph has something to do with acceleration. And you'd be right. Just as the slope of a velocity-time graph is acceleration, the slope of a distance-t2 graph is acceleration. Well, not quite. It's actually ONE HALF the acceleration.
6
negative one and a half
You can get half-life from a graph by picking two points where the (radio)activity decays to one half its value. The interval of time of those two points is the half-life. You can confirm by picking more points, again with a half (radio)activity value and see that the time is the same in each case.
the graph of y = |x| (absolute value of x) looks like a V with the point of the V at the origin. When x is negative (left half of graph), the line y = -x coincides with |x| so this half has a slope of -1. When x is positive (right half of graph), the line y = x coincides with |x| so this half has a slope of +1.
The graph of that function looks like a big letter ' V '. The point of the 'V' is at the origin,the left half has slope = -3, and the right half has slope = 3.
Since distance is 1/2 at^2 where a is acceleration, it represents one half of the acceleration
That's unusual. I guess your teacher is trying to make you think a bit. It's a good mental exercise, though. You may recall that the units of acceleration are meters per second squared. That gives you a clue right there. And if you knew Calculus, you'd know that acceleration is the second derivative of distance, s, with respect to time, t: d2s/dt2. So, by now you're probably getting the feeling that the slope of a distance-time squared graph has something to do with acceleration. And you'd be right. Just as the slope of a velocity-time graph is acceleration, the slope of a distance-t2 graph is acceleration. Well, not quite. It's actually ONE HALF the acceleration.
A discrete graph is one where one or both variables can only take a some values. These are usually integer values but need not be. For example, shoe sizes (in UK) go up in half units. A non-linear graph is one in which the points of the graph do not lie on a straight line.
"A point is that which has no part" --Euclid All points are identical -- they only have location (usually in the form of X/Y coordinates), no other properties. Angles also have magnitude (how wide they are, in degrees or radians) and lines have slope. Rays have slope, as well as a single endpoint (they are "half of a line" so to speak). Line segments have two endpoints.
Normally it is not.
+2
y=1/2 X-3.what is the slope?