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It can be shown that:

- height = (d tan α tan β)/(tan α - tan β)

- α is the angle closest to the object
- β is the angle further away from the object
- d is the distance from the point of angle α to the point of angle β

height = (53 ft × tan 31.4° × tan 26.4°)/(tan 31.4° - tan 26.4°) ≈ 140.87 ft

Q: What is the height of a building if the angle of elevation to the top from a point on the ground is 31.4 degrees and from 53 feet further back it is 26.4 degrees?

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tan40=x/100 100tan(40)=83.9m

The question is not quite clear but if the angle of elevation is 26 degrees at a distance of 165 feet away from the building then its height is 80.47587711 feet. 165*tan(26) = 80.47587711 feet

If the engineer's eye is at ground level, then the distance to the point on the building underneath its highest point is 450/tan(22) ft. If the engineer was standing and his eyes were x ft above the ground, the distance is (450-x)/tan(22) ft.

Using the formula: tangent = opposite/adjacent whereas tangent angle = height/ground distance, will help to solve the problem

If you are looking for the angle of elevation from the ground to the top of Qutub Minar, here is a solution. Qutub Minar is 72.5 meters tall. The angle of elevation would equal arctan(72.5/5). It comes out to approximately 86.05 degrees.

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tan40=x/100 100tan(40)=83.9m

The question is not quite clear but if the angle of elevation is 26 degrees at a distance of 165 feet away from the building then its height is 80.47587711 feet. 165*tan(26) = 80.47587711 feet

If the engineer's eye is at ground level, then the distance to the point on the building underneath its highest point is 450/tan(22) ft. If the engineer was standing and his eyes were x ft above the ground, the distance is (450-x)/tan(22) ft.

7 degrees

Using the formula: tangent = opposite/adjacent whereas tangent angle = height/ground distance, will help to solve the problem

51.34019175 degrees or as 51o20'24.69''

It can mean the height from the ground to the roof peak, or the ground elevation above or below sea level.

Using trigonometry and the sine ratio the distance is 959 meters to the nearest meter.

Length of line: 90/cos(22) = 97 feet rounded to nearest the foot

If you are looking for the angle of elevation from the ground to the top of Qutub Minar, here is a solution. Qutub Minar is 72.5 meters tall. The angle of elevation would equal arctan(72.5/5). It comes out to approximately 86.05 degrees.

A radio altimeter bounces radio waves off the ground to detect elevation.

A depression in the ground with a higher elevation on either side.