Using trigonometry and the sine ratio the distance is 959 meters to the nearest meter.
Required angle has a tangent of 7.6/6.1 ie 1.249. This is 51.25 degrees.
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45 Degrees is exactly between 90 and 0 degrees so it is the maximim shot. If you shoot something 90 degrees it would go straight up. If you shoot somthing 0 degrees it hits the ground fastest because of gravity. But the 45 degree angle allows for the most lift and distance for an object to travel.
82.4 in
Height - is the distance from the ground to the top of an object... width is the distance across the widest part... and depth is the measurement from front to back.
Draw a right triangle. The balloon is at the top of the short side, and the base is the distance from the person's hand along a path parallel to the ground to where the balloon hovers. Since the angle is 35 degrees, we want the length of that short side, and we get it using the sine function of trigonometry. Sine = opposite over hypotenuse, so we can write an equation where "x" is the short side: x/30 = sin35 x/30 = 0.5736 x = 17.21 Now add to this the 6.5 feet that the person's hand is off the ground, and the balloon is 23.71 feet above the ground.
If you are looking for the angle of elevation from the ground to the top of Qutub Minar, here is a solution. Qutub Minar is 72.5 meters tall. The angle of elevation would equal arctan(72.5/5). It comes out to approximately 86.05 degrees.
The question is not quite clear but if the angle of elevation is 26 degrees at a distance of 165 feet away from the building then its height is 80.47587711 feet. 165*tan(26) = 80.47587711 feet
Using trigonometry the height of the hill works out as 115.58 meters rounded to two decimal places
7 degrees
Using the formula: tangent = opposite/adjacent whereas tangent angle = height/ground distance, will help to solve the problem
By drawing a sketch from the given information and then using trigonometry the height of the mountain works out as 546 meters rounded to the nearest whole number.
If the engineer's eye is at ground level, then the distance to the point on the building underneath its highest point is 450/tan(22) ft. If the engineer was standing and his eyes were x ft above the ground, the distance is (450-x)/tan(22) ft.
15*cos(60) = 7.5 7.5 m
51.34019175 degrees or as 51o20'24.69''
Depends on 2 things. 1. The height of the balloon. The higher it is, the greater the distance between April and the balloon. 2. The direction of both in relation to you. Presuming the balloon is at ground level, if both are in the same direction, then the distance between them is 500 minus 275 ft. If they are in opposite directions then the distance is 500 plus 275 ft. If they are in varying directions the answer could be anything between these two results.
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