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An engineer on the ground is looking at the top of a building the angle of elevation to the top of the building is 22 degrees the engineer knows the building is 450 ft tall what is the distance?
Wiki User
∙ 14y ago
If the engineer's eye is at ground level, then the distance to the point on the building underneath its highest point is 450/tan(22) ft. If the engineer was standing and his eyes were x ft above the ground, the distance is (450-x)/tan(22) ft.
Wiki User
∙ 14y ago
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What is the angle of elevation from the top of a bluilding from a point 165 feet away from the building on ground level is 26 degrees what is the height of the building?
The question is not quite clear but if the angle of elevation is 26 degrees at a distance of 165 feet away from the building then its height is 80.47587711 feet. 165*tan(26) = 80.47587711 feet
The angle of elevation to the top of a building from a position on the ground 100 meters from the base of the building is 40 degrees how tall is the building?
tan40=x/100 100tan(40)=83.9m
If the angle of elevation of the sun is 52.6 degrees and the height of a building is 18.6m the building casts a shadow of 12.3m 14.2m 16.4m 14.9m or none of those?
18.6 m/52.6 degrees tan= 14.2
What is the approximate height of a building when the angle of elevation at the top of a building is 34 degrees and at a point 80 feet closer the angle of elevation is 45 degrees?
It can be shown that:height = (d tan α tan β)/(tan α - tan β)where: α is the angle closest to the objectβ is the angle further away from the objectd is the distance from the point of angle α to the point of angle βThus: height = (80 ft × tan 45° × tan 34°)/(tan 45° - tan 34°) ≈ 165.78 ft
What is the elevation of sea level?
the elevation of sea level is 0 degrees.
A building is 120 feet high. at a certain distance away from the building. an observer notices the angle of elevation to the top of the building is 41 degrees. how far is the observer from the base of the building?
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What is the angle of elevation from the top of a bluilding from a point 165 feet away from the building on ground level is 26 degrees what is the height of the building?
The question is not quite clear but if the angle of elevation is 26 degrees at a distance of 165 feet away from the building then its height is 80.47587711 feet. 165*tan(26) = 80.47587711 feet
When you are building weight in a haircut the hair should be held at what elevation?
below 90 degrees
The angle of elevation to the top of a building from a position on the ground 100 meters from the base of the building is 40 degrees how tall is the building?
tan40=x/100 100tan(40)=83.9m
If the angle of elevation of the sun is 52.6 degrees and the height of a building is 18.6m the building casts a shadow of 12.3m 14.2m 16.4m 14.9m or none of those?
18.6 m/52.6 degrees tan= 14.2
What is the approximate height of a building when the angle of elevation at the top of a building is 34 degrees and at a point 80 feet closer the angle of elevation is 45 degrees?
It can be shown that:height = (d tan α tan β)/(tan α - tan β)where: α is the angle closest to the objectβ is the angle further away from the objectd is the distance from the point of angle α to the point of angle βThus: height = (80 ft × tan 45° × tan 34°)/(tan 45° - tan 34°) ≈ 165.78 ft
What is the elevation of sea level?
the elevation of sea level is 0 degrees.
What is the distance from a point on the ground at an angle of elevation of 9 degrees to a hot air balloon that is 150m above the ground?
Using trigonometry and the sine ratio the distance is 959 meters to the nearest meter.
What is the height of a tower when the distance between its angles of elevation are 32 degrees and 43 degrees is 8 meters?
Using trigonometry the height of the tower works out as 15.2 meters rounded to one decimal place.
How tall is a building with a 73 ft shadow when elevation of the sun is 31 degrees?
(Height of the building)/(length of the shadow) = tangent of 31° .Height = 73 tan(31°) = 43.9 feet (rounded)
How can you give examples for absolute location?
Absolute location is typically defined by 3 (sometimes 4 variables): Latitude (distance from equator measured in degrees, minutes and seconds), longitude (distance from the prime meridian also given in degrees, minutes and seconds), elevation (distance above/below sea level) and sometimes time.
What is the Angle of elevation of Qutub Minar when you are at a distance of 5metre using trigonometry?
If you are looking for the angle of elevation from the ground to the top of Qutub Minar, here is a solution. Qutub Minar is 72.5 meters tall. The angle of elevation would equal arctan(72.5/5). It comes out to approximately 86.05 degrees.
