19.6 meters / 64.4 ft
a. 144 feet b. 96 ft/sec.
depends on the mass of the stone, the shape of the stone, and the height dropped from. sorry dude.
89
240 ft
Assuming they were in a vacuum, if both objects were dropped from th esame height, then both take the same length of time to reach the ground. All masses fall with the same acceleration, reach the same speed in the same period of time, and hit the ground at the same time. Otherwise and if there is an atmosphere or if they are dropped from different heights, you have not presented information; shape and size are the most important factors.
4 seconds
a. 144 feet b. 96 ft/sec.
Regardless of the height from which it is falling, (neglecting air resistance) it's speed will be 19.62 metres per second. (Acceleration from gravity is 9.81 metres per second squared, so after 1 second it is moving at 9.81 metres per second and after 2 seconds it is moving at 19.62 metres per second.
This is the vertical motion model, used when solving for height that an object is dropped from, what height an object is at after so many seconds, what rate the object is falling at, and how many seconds have passed after dropping an object when it is at x height etc. etc. Most often used in Algebra 1 and 2.
Assuming you have the same mass you could use the formula h=-16t^ 2+ c H stands for height of falling object after time c stands for height dropped from t stands for time
as done in Galileo's experiment when he dropped a large rock and a feather from a tall tower both hit the ground at the same moment when dropped from the same height.
A pebble is dropped from the top of a 144-foot building. The height of the pebble h after t seconds is given by the equation h=−16t2+144 . How long after the pebble is dropped will it hit the ground?Interpretationa) Which variable represents the height of the pebble, and in what units?b) Which variable represents the time in the air, and in what units?c) What equation relates the height of the object to its time in the air?d) What type of equation is this?e) What are you asked to determine?
They will hit the ground simultaneously. Gravitational pull is the same on all matter.
381 metres
Yes
The ESB is much wider at its base than at its top, so no object dropped from its top would hit the sidewalk. HOWEVER, an object dropped from the height of the ESB would, if it experienced no air friction nor hit anything along the way, would hit the ground in 8.8 seconds. However, air friction would delay this by a few seconds, as a small ball would experience air resistance before that time.
depends on the mass of the stone, the shape of the stone, and the height dropped from. sorry dude.