7 in
Area of a triangle = 0.5*b*h0.5*2*6 = 6 in2
the formula for finding the area of a triangle is 1/2base * height. so 1/2(6.2) * 4.5 = 13.95 in2
58.5 in2 (9*13/2)
Area = 1/2bh Area = 1/2(4 in)(4 in) = 8 in2 =====
It is 22 in2. Multiply 4 by 11 and divide by 2.
area of a triangle = 0.5 * base * height. Hence, the base of the triangle = 2 * area / height = 2 * 90 [in2] / 12 [m] we know 1 [m] = 39.37 [in] or equivalently, 1 = 39.37 [in/m] Therefore, base = 2 * 90 [in2] / (12 [m] * 1) = 2 * 90 [in2] / (12 [m] * 39.37 [in/m] ) = 2 * 90 [in] / (12 * 39.37 ) = 0.381 [in] =============== area=basexheight/2 bring two over to ninety side 90x2=180 180=12xbase 180/12=15 base=15 =============== The second author above has forgotten about the units -- the area given is in square inches and the height is in meters.
The formula for the area of a triangle is 1/2bh, so one-half of the base times the height. With a base of 18 inches, one half of the base would be 9 inches. This, multiplied by the height of 20m converted to inches (787.4 inches) gives the problem 9 x 787.4 = 7086.6 in2, or 49.212 ft2
Formula for the area of a triangle is 1/2(b*h). Just plug the numbers in. 1/2(8.7*15.6) = 1/2(135.72) = 67.86 in2
Yes they are similar
The triangle has an area of 28 square inches. To find the area of a triangle, we use the formula here: Atriangle = 1/2 x Base x Height A = 1/2 x b x h or just 1/2 bh Plug in the base, which is 7, and the height, which is 8, and take 1/2 times 7 times 8, which is 1/2 times 56, which is 28 in2.
You get two congruent right triangles when you divide a rectangle diagonally. (This is one way to show that the area of each of those triangles is 1/2*base*height. Rectangle area = (4 in)(8 in) = 32 in2. Triangle area = (1/2)(4 in)(8 in) = 16 in2.)
You get two congruent right triangles when you divide a rectangle diagonally. (This is one way to show that the area of each of those triangles is 1/2*base*height. Rectangle area = (4 in)(8 in) = 32 in2. Triangle area = (1/2)(4 in)(8 in) = 16 in2.)