The formula for the area of a triangle is 1/2bh, so one-half of the base times the height. With a base of 18 inches, one half of the base would be 9 inches. This, multiplied by the height of 20m converted to inches (787.4 inches) gives the problem 9 x 787.4 = 7086.6 in2, or 49.212 ft2
The area of a triangle is (1/2) x (length of the base) x (height of the triangle). You ought to be able to handle it from this point.
Area is 108 units2
Area = 0.5*base*height = 0.5*18*20 = 180 metres2
If a right triangle has an area of 81 meters an a base of 9 meters its height is: 18 meters.
The area of triangle is : 18.0
The area of triangle is : 135.0
The area of a triangle is (1/2) x (length of the base) x (height of the triangle). You ought to be able to handle it from this point.
The area is 117 units2
Area is 108 units2
Area = 0.5*base*height = 0.5*18*20 = 180 metres2
If a right triangle has an area of 81 meters an a base of 9 meters its height is: 18 meters.
Area of traingle = Base * Height / 2 = 18*12/2 = 108 m2
Area = 0.5*12*18 = 108 square inches
The area of triangle is : 18.0
Area=18. Area= Base * height / 2 (12*3)/2
Oh, dude, so you got this triangle with a base of 9 meters and an area of 81 square meters, right? Well, the height of that bad boy is technically 18 meters. Yeah, it's like basic math or whatever. So, there you go, the height is 18 meters, like, no big deal.
Area = (1/2) x base x height , so solve this for height; height = 2 x Area / base height = (2)(81)/(9) = 18