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How do you solve 4x equals 12x plus 32?
OK, SO 4x = 12x + 32.SO 4x -12x-12x-12x+32 (subtract 12x from each side to get x on one side)SO -8x = 32 (simplify)SO -1 (-8x) = 32 (-1) (multiply each side by -1)SO 8x -32 (simplify)SO 8x / 8 = -32/8 (divide each side by eight (8) to get ""X"" by itself)SO x= -4SO x = -4.Does that help?Hope that helps!
Factor the following polynomial x2 plus 12x plus 32?
x2 + 12x + 32 = (x + 8)(x + 4)
What is the integral of x-12?
∫(x - 12) dx = x2 / 2 - 12x + C
What is the polynomial of this factor x2 plus 12x plus 32 in descending order?
x2 + 12x + 32 = (x + 4)(x + 8)
Integral lnx2 1?
If you mean integral ln(x2+1)dx, it is 2tan-1(x)+x[ln(x2+1)-2]. To find this and other integrals, go to http://integrals.wolfram.com/index.jsp?expr=ln(x^2%2B1)&random=false It can solve nearly every integral I've encountered.
How do you solve 6y equals 12x plus 32?
6y = 12x+32 Divide all terms by 6: y = 2x+5 and 1/3 which is now in slope intercept form
What is the Second derivative of lnx2?
d/dx(lnx2) = 2/x ===== d/dx2(2/x) use product rule 2'*x - 2 *x'/x2 = - 2/x2 -----------
X2 -12x plus 32?
x2 - 12x + 32 = 0 x2 - 8x - 4x +32 = 0 x(x -8) - 4(x -8) = 0 (x - 4)(x - 8) = 0 x = 4 or x = 8
4x plus 32 equals 12x - 8?
Are you trying to find x? If so, get all x's to one side, 32=8x-8, then get x alone... 40= 8x then divide by 8... 5=x So at x=5, 4x+32=12x-8
What is X2 plus 12x plus 32 factor?
(x + 4)(x + 8)
How do you factor x squared -12x plus 32?
(x - 8)(x - 4)
What is the answer to 12x plus 4 equals 4x-20?
Subtract 4 from both sides. 12x = 4x - 24 Subtract 4x from both sides. 8x = -24 x = -3 Check it. -36 + 4 = -12 - 20 -32 = -32 It checks.
