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∫ sin(x)/cos2(x) dx = sec(x) + C

C is the constant of integration.

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โˆ™ 2010-11-05 04:14:26
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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: What is the integral of the sine of x divided by the cosine squared of x with respect to x?
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Related questions

What is the integral of 1 divided by the cosine squared of x with respect to x?

∫ 1/cos2(x) dx = tan(x) + C C is the constant of integration.


What is the integral of the cosine of x divided by the sine squared of x with respect to x?

∫ cos(x)/sin2(x) dx = -cosec(x) + C C is the constant of integration.


What is sine squared theta subtract six cosine squared theta divided by one minus seven cosine squared theta?

It is 1.


Can you make cosine squared X divided by2 equal to cosine squared x with some constant?

You could just pull out the half: it will be (1/2) cos squared x.


What is the integral of 1 divided by the square of the hyperbolic cosine of x with respect to x?

∫ 1/cosh2(x) dx = tanh(x) + C C is the constant of integration.


What is the integral of 1 divided by the cosine of x with respect to x?

∫ 1/cos(x) dx = ln(sec(x) + tan(x)) + C C is the constant of integration.


What is cosine squared theta equal to'?

Cosine squared theta = 1 + Sine squared theta


What is the integral of cosine cubed?

The integral of cosine cubed is sinx- 1/3 sin cubed x + c


What is the integral of the cosine of x with respect to x?

∫ cos(x) dx = sin(x) + CC is the constant of integration.


1 minus 2 cosine squared divided by sine cosine is equal to tangent minus cotangent?

No, it is not. To be correct, the expression requires parenthesis, which are missing.


Is 2 cosine x the same as cosine squared x?

No


Do the equations sine plus cosine and sine squared plus cosine squared both equal 1?

No, they do not.

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