7560 degrees
a convex polygon has 6 sides . What is the sum of the measure of its interior angles?
No, a convex polygon cannot have an interior angle sum of 400 degrees. The sum of the interior angles of a convex polygon is always equal to (n-2) * 180 degrees, where n is the number of sides. Since the sum of the interior angles must be greater than 180 degrees for each interior angle, a convex polygon with an interior angle sum of 400 degrees would require at least 9 sides, which would make it a nonagon, not a polygon.
The sum of the interior angles of a triangle is 180 deg. For a convex polygon with n sides we can divide it to n-2 triangles. So the answer, if the polygon is convex, is (13-2)*180= 1980 deg * * * * * The polygon need not be convex. The formula for the sum of the interior angles is valid as long as the polygon is simple - that it, its sides do not cross each other inside the polygon.
The sum of the interior angles of a convex polygon can be calculated using the formula ( (n - 2) \times 180^\circ ), where ( n ) is the number of sides in the polygon. For example, a triangle (3 sides) has a sum of ( 180^\circ ), a quadrilateral (4 sides) has ( 360^\circ ), and so on. This formula applies to any convex polygon, regardless of the number of sides.
33 sides
It will have 35 sides and can be described as a 35-agon
It is: (5940+360)/180 = 35 sides
The sum of the interior angles of any polygon of n sides is equal to 180(n - 2) degrees.
for novanet - 9,540
360 degrees
icosikaipentagon or pentacosagon
9540 degrees