The sum of the interior angles of a triangle is 180 deg.
For a convex polygon with n sides we can divide it to n-2 triangles.
So the answer, if the polygon is convex, is (13-2)*180= 1980 deg
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The polygon need not be convex. The formula for the sum of the interior angles is valid as long as the polygon is simple - that it, its sides do not cross each other inside the polygon.
There is no regular polygon with an interior angle of 20o. If the interior angle is 120o then there are six sides and the sum of the angles is 720o.
The sum of each pair of interior and exterior angles of a polygon is always 180 degrees.
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There is no regular polygon with an interior angle of 20o. If the interior angle is 120o then there are six sides and the sum of the angles is 720o.
The sum of the interior angles of a polygon with n sides is 180*(n-2) degrees.
A 29-sided polygon.
A pentagon
No
The sum of each pair of interior and exterior angles of a polygon is always 180 degrees.
Im stuck on that too :/
360 ________________________________________________ Sum of Interior Angles of a Polygon = 180 (n-2) Sum of Exterior Angles of a Polygon = 360 The sum of an angle and an exterior angle of a regular polygon is 360
(number of sides -2)*180 = sum of interior angles
The method of finding the sum of the interior angles of a polygon is by multiplying the (number of sides)-2 by 180, so the sum of the interior angle measures in a 25-sided polygon would be 23*180, or 4140 degrees.
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