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The largest number with 5 digits is 9999999999/14=7142.785714285714
take all the nos before the decimal point
7142 * 14 = 99988
so 99988 is the largest number with 5 digits that is divisible by 14.
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I am a 2-digit number divisible by 19 The sum of your digit is 14 What number are you and why?
Simple.2 digits numbers that are divisible by 19 are: 19, 38, 57, 76, 95The only one whose digits add to 14 is 95, 9+5 = 14
The largest two digit number that can be rounded off to 10?
14
What is the largest two-digit number that can be rounded off to 10?
14
Is 95 is divisible by 9?
No. To be divisible by 9 the sum of the digits must also be divisible by 9. As the sum must be divisible by 9, the check can also be applied to the sum; so keep summing until a single digit remains, then if, and only if, this single digit is 9 is the original number divisible by 9 (the single digit gives the remainder when the original number is divided by 9 and is known as the digital root of the number). For 95: 95 → 9 + 5 = 14 14 → 1 + 4 = 5 5 ≠ 9 → 95 is not divisible by 9. (The remainder when 95 is divided by 9 is 5).
What are the divisibility rules for 1-13?
14
The smallest two digit number that is divisible by 7?
14
What is a 2 digit number divisible by 19 The sum of the digits is 14 What is this number?
the answer is 95
What is largest 14 digit number?
99999999999999
What is the largest 3-digit multiple of 14?
-11
I am a 2-digit number divisible by 19 The sum of your digit is 14 What number are you and why?
Simple.2 digits numbers that are divisible by 19 are: 19, 38, 57, 76, 95The only one whose digits add to 14 is 95, 9+5 = 14
The largest two digit number that can be rounded off to 10?
14
What is the largest two-digit number that can be rounded off to 10?
14
What is a three digit number that is less than one hundred fifty that is divisible by eight?
112 is less than 150 & is divisible by 8 ( 14 ).
How many 3 digit numbers are divisible by 7?
The smallest 3-digit multiple of 7 is 105 = 15*7 The largest 3-digit multiple of 7 is 994 = 142*7 So there are 142-14 = 128 3-digit multiples of 7, ie 128 3-digit numbers that are divisible by 7.
How many 2 digit numbers are divisible by 7?
All 2 digit numbers are divisible by 7: it is simply that some of the quotients are not whole numbers. 10/7 = 1 3/7 99/7 = 14 1/7 So the number of 2-digit numbers which are evenly divisible by 7 are 14-1 = 13.
Is 95 is divisible by 9?
No. To be divisible by 9 the sum of the digits must also be divisible by 9. As the sum must be divisible by 9, the check can also be applied to the sum; so keep summing until a single digit remains, then if, and only if, this single digit is 9 is the original number divisible by 9 (the single digit gives the remainder when the original number is divided by 9 and is known as the digital root of the number). For 95: 95 → 9 + 5 = 14 14 → 1 + 4 = 5 5 ≠ 9 → 95 is not divisible by 9. (The remainder when 95 is divided by 9 is 5).
What is the divisible rule for 7?
To discover whether a number is divisible by 7, double the last digit of the number, and subtract it from the rest of the number. If the result is either 0 or divisible by 7, then the number is divisible by 7. For example:672 - last digit is 2, double 2 to make 4, subtract from 67 equals 63, 63/7 = 9, therefore, 672 is divisible by 7.Dividing by 7 (2 Tests)Take the last digit in a number.Double and subtract the last digit in your number from the rest of the digits.Repeat the process for larger numbers.Example: 357 (Double the 7 to get 14. Subtract 14 from 35 to get 21 which is divisible by 7 and we can now say that 357 is divisible by 7. NEXT TESTTake the number and multiply each digit beginning on the right hand side (ones) by 1, 3, 2, 6, 4, 5. Repeat this sequence as necessaryAdd the products.If the sum is divisible by 7 - so is your number.Example: Is 2016 divisible by 7?6(1) + 1(3) + 0(2) + 2(6) = 2121 is divisible by 7 and we can now say that 2016 is also divisible by 7.
