Simple.2 digits numbers that are divisible by 19 are: 19, 38, 57, 76, 95The only one whose digits add to 14 is 95, 9+5 = 14
14
14
Oh, what a delightful little puzzle we have here! To find a four-digit number that is divisible by both 8 and 9, we can look for a number that is divisible by their least common multiple, which is 72. So, let's find a multiple of 72 that is a four-digit number, like 1008. Such a harmonious number, don't you think?
No. To be divisible by 9 the sum of the digits must also be divisible by 9. As the sum must be divisible by 9, the check can also be applied to the sum; so keep summing until a single digit remains, then if, and only if, this single digit is 9 is the original number divisible by 9 (the single digit gives the remainder when the original number is divided by 9 and is known as the digital root of the number). For 95: 95 → 9 + 5 = 14 14 → 1 + 4 = 5 5 ≠ 9 → 95 is not divisible by 9. (The remainder when 95 is divided by 9 is 5).
14
the answer is 95
99999999999999
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Simple.2 digits numbers that are divisible by 19 are: 19, 38, 57, 76, 95The only one whose digits add to 14 is 95, 9+5 = 14
14
14
Oh, what a delightful little puzzle we have here! To find a four-digit number that is divisible by both 8 and 9, we can look for a number that is divisible by their least common multiple, which is 72. So, let's find a multiple of 72 that is a four-digit number, like 1008. Such a harmonious number, don't you think?
112 is less than 150 & is divisible by 8 ( 14 ).
No, 87 is not divisible by 7. To determine if a number is divisible by 7, you can use the rule that states a number is divisible by 7 if the difference between twice the digit in the ones place and the number formed by the other digits is either 0 or a multiple of 7. In this case, the number formed by the other digits is 8, and twice the digit in the ones place is 14. The difference between 14 and 8 is 6, which is not a multiple of 7, so 87 is not divisible by 7.
The smallest 3-digit multiple of 7 is 105 = 15*7 The largest 3-digit multiple of 7 is 994 = 142*7 So there are 142-14 = 128 3-digit multiples of 7, ie 128 3-digit numbers that are divisible by 7.
All 2 digit numbers are divisible by 7: it is simply that some of the quotients are not whole numbers. 10/7 = 1 3/7 99/7 = 14 1/7 So the number of 2-digit numbers which are evenly divisible by 7 are 14-1 = 13.