42
LA=1/2ps
The lateral area [L] of a right prism with base perimeter [P] and height [h] is L=Ph.
Area of each triangular face = 4*sqrt(3) sq ft = 13.86 sq ft (to 2 dp) Area of each rectangular face = 40 sq ft Total area = 2*13.86 + 3*40 = 147.71 sq ft
The lateral area [L] of a right prism with base perimeter [P] and height [h] is L=Ph.
The lateral area of a triangular prism is found by computing the perimeter of the triangular base (sum of the three sides) and multiplying it by the height of the prism. If the triangular base has sides of length s1, s2, and s3, and the height of the prism is h, then each lateral face of the prism would be a rectangle. The area of one face of the prism would be (s1 x h), the area of the second face of the prism would be (s2 x h), and the area of the third face of the prism would be (s3 x h). So the three lateral faces would have a total area of (s1 x h) + (s2 x h) + (s3 x h), or equivalently (s1 + s2 + s3) x h; i.e., (the perimeter of the triangular base) x (the height of the prism).
225 units squared
240 units squared
Why do you need to FIND the slant height if you have the [lateral height and] slant height?
The height of the triangular face of a pyramid is called the slant height.
no its 270Edit by: ArteomNO ITS 270 Units Squared
The lateral area L.A. of the right triangular prism is the sum of the areas of its lateral faces, which are rectangles with length the height (l = h = 15) and wide the sides of the triangle (w1 = leg1 = 3, w2 = leg2 = 5, w3 = hypotenuse = 7). So we have: L.A. = (15 x 3) + (15 x 5) + (15 x 7) L.A. = 15(3 + 5 + 7) L.A. = 225 Thus, we can also say that the lateral area of a prism is the product of the perimeter of its base with the height of the prism.
Lateral Area=Perimeter of the base * height perimeter=20 height=6 so, Lateral Area=20 * 6 Lateral Area=120cm