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In other words, we require a sequence of consecutive numbers none of which are prime.

This can be guaranteed if we obtain (10 + 1)! = 39916800

Then clearly, 39916800 + 2 is divisible by 2, 39916800 + 3 is divisible by 3, and so on to 39916800 + 11 is divisible by 11.

Consequently, all ten numbers from 39916802 - 39916811 are composite.

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Q: What is the least counting number that could be the first of 10 or more consecutive composite?
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