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Since the question did not specify a rational polynomial, the answer is a polynomial of degree 3.

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Q: What is the least degree a polynomial could have with an imaginary root with a multiplicity of three?
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How many real roots will a 3rd degree polynomial have?

A third degree polynomial could have one or three real roots.


Is 21 a polynomial?

Not in the normal sense but it could be considered a degenerate polynomial of degree 0.


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Good question! The zero polynomial "0" could result from any of the following: (0), (0)x, (0)x2, (0)x3, etc. Since you don't know which it came from, you can't say what the degree is.


Can you find a third degree polynomial equation with rational coefficients that has the given numbers as roots 3i and 7?

Yes, easily. Even though the question did not ask what the polynomial was, only if I could find it, here is how you would find the polynomial: Since the coefficients are rational, the complex (or imaginary) roots must form a conjugate pair. That is to say, the two complex roots are + 3i and -3i. The third root is 7. So the polynomial, in factorised form, is (x - 3i)(x + 3i)(x - 7) = (x2 + 9)(x - 7) = x3 - 7x2 + 9x - 63


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Which of these terms could be an imaginary disease?

senoritis