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Since the question did not specify a rational polynomial, the answer is a polynomial of degree 3.

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Q: What is the least degree a polynomial could have with an imaginary root with a multiplicity of three?
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How many real roots will a 3rd degree polynomial have?

A third degree polynomial could have one or three real roots.


Is 21 a polynomial?

Not in the normal sense but it could be considered a degenerate polynomial of degree 0.


What degree is a polynomial?

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Good question! The zero polynomial "0" could result from any of the following: (0), (0)x, (0)x2, (0)x3, etc. Since you don't know which it came from, you can't say what the degree is.


Can you find a third degree polynomial equation with rational coefficients that has the given numbers as roots 3i and 7?

Yes, easily. Even though the question did not ask what the polynomial was, only if I could find it, here is how you would find the polynomial: Since the coefficients are rational, the complex (or imaginary) roots must form a conjugate pair. That is to say, the two complex roots are + 3i and -3i. The third root is 7. So the polynomial, in factorised form, is (x - 3i)(x + 3i)(x - 7) = (x2 + 9)(x - 7) = x3 - 7x2 + 9x - 63


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What is the degree of polynomial of 2x2y-4x5y7 plus 14xy plus 3?

Due to shortcomings of the browser, I regret that it is impossible to tell. For example, the first term could be 2x times 2y or 2x-squared times y. Some educated guesswork suggests degree 12 - from the second term, but I could be wrong.


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It is non-linear relationship. This could be a polynomial relationship where the polynomial is of order > 1. Or it could be any other algebraic, trigonometric, exponential, logarithmic, hyperbolic, etc relationship. It could be a step relationship, or could even be a random mapping.


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Which of these terms could be an imaginary disease?

senoritis