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387.

A number 2 more than a multiple of 5, 7 and 11 is required.

The smallest such number is 2 more than the lowest common multiple of 5, 7 and 11.

The LCM of 5, 7 & 11 is 385

⇒ 385+2 = 387

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Q: What is the least number that gives you a remainder of 2 when divided by 5 7 or11?
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