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The numbers divided by 5 gives 1 remainder means it should end either 1 or 6. But in case of number ends with 6 will be divided by 2. So only number ending with 1 have to consider. Also the number should be divisble by 7. So when number ending with 3 is multiplied by 7 will give result of number ending 1. So, possibilities are 7*3, 7*13, 7*23, etc

In that least number which solves this problem 7*43 = 301.

So the least possible number is 301.

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Q: What is the number divided by 2 3 4 5 6 gives reminder 1 and remainder 0 if it divided by 7?
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