It is: 470
1
To make a number divisible by 10, its last digit must be 0. The last digit of 23483 is 3. Therefore, to make it divisible by 10, you should subtract 3 from 23483. This means the least number that should be subtracted is 3.
It is 1 so that 7310 is divisible by 5 or 10
180 is divisible by 2, 3, 4, 5, 9, and 10.
2520
It's not prime - it's divisible by at least 2,3,5,9 & 10
If a number ends with 0, it is divisible by 10.If a number ends with 0, it is divisible by 10.If a number ends with 0, it is divisible by 10.If a number ends with 0, it is divisible by 10.
To find a number that is divisible by both 2458 and 10, we need to find the least common multiple (LCM) of the two numbers. The LCM of 2458 and 10 is the smallest number that is a multiple of both 2458 and 10, which is 24580. Therefore, 24580 is the number that is divisible by both 2458 and 10.
The smallest number that is divisible by 2, 6, and 10 is 30
Every number divisible by 10 is divisible by 5.
No, a number that is divisible by 10 will not always be divisible by 4. For a number to be divisible by 10, it must end in 0. However, for it to be divisible by 4, the last two digits of the number must form a number that is divisible by 4. For example, the number 30 is divisible by 10 but not by 4, as 30 divided by 4 does not yield an integer.
A number that is divisible by 2, 3, 4, 5, and 10 must be divisible by the least common multiple of these numbers, which is 60. Therefore, any number that is a multiple of 60 will be divisible by 2, 3, 4, 5, and 10. This is because 60 is the smallest number that contains all the prime factors of 2, 3, 4, 5, and 10.