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How do you find the number z such that the proportion of observations that are less than z in a standard Normal distribution is 0.7?
You will need to use tables of z-score or a z-score calculator. You cannot derive the value analytically.The required z-score is 0.524401
What to do when the z score is not in the z score chart?
The average z score chart lists z scores with three significant figures. For example, you can find the z score -1.81 on the chart, but not -1.812 or -1.818. In the case that you wish to look up a z score with more than three significant figures, round it to three significant figures and then use the chart. OR You can also use a calculator if you wish to get more accurate results. The link for calculator is mentioned below.
How do you find p value with z score only?
You either look it up in a table of z scores or you can use a calculator such as the TI8 and use normalcdf.
How do I put arcsec in calculator?
Divide "1" by the argument "z" of the arcsec(z) function. Note, that "z" is equal to secant(angle) and 1/z is cosine (angle).For example, if arcsec(4) then cosine is "1/4" value or 0.25.Using a calculator, calculate the arccosine (arccos) function of "1/z" to get arcsec(z). Angle=arcsec(z)= arccos(1/z).In the example, arcsec(4)= arccos(0.25)=75.52 degrees.Calculate arcsecant if the function is given as arcsec(sec(Z)) e.g. arcsec(sec(45)). In such a case you do not need to calculate the secant value and then follow Steps 1 and 2. Instead, get an instant answer: arcsec equals Z. In this example, arcsecant of sec(45) is 45.
7x+(5x6)z?
7x + 30xz I use the symbolab calculator to solve math equations I can't figure out :)
What is the value of z if the area between -z and z is 0.754?
Since the normal distribution is symmetric, the area between -z and 0 must be the same as the area between 0 and z. Using this fact, you can simplify this problem to finding a z such that the area between 0 and z is .754/2=.377. If you look this value up in a z-table or use the invNorm on a calculator, you will find that the required value of z will be 1.16. Therefore, the area between -1.16 and 1.16 must be approximately .754.
Write a program that will add the number specified by the user?
In BASIC, this could be as simple as: 10 Input X 20 Input Y 30 Z=X+Y 40 Print X;" + ";Y;" = ";Z 50 END In JAVA... /** * A simple calculator that adds, subtracts, multiplies, and divides. * Written in Java by: AustinDoggie */ public class Calculator() { public Calculator() { // don't really have to do anything here } public int add(int x, int y) { int z = x + y; // add two numbers return z; // and return it } public int subtract(int x, int y) { int z = x - y; // subtract two number return z; // and return it } public int multiply(int x, int y) { int z = x*y; // multiply two number return z; // and return it } public int divide(int x, int y) { int z = x/y; // divide two numbers return z; // and return the result } } Hope that helps.
What is the area under the normal curve between z -1.0 and z -2.0?
The area under the normal curve between z = -1.0 and z = -2.0 can be found using the standard normal distribution table or a calculator. The area corresponds to the probability of a z-score falling within that range. For z = -1.0, the cumulative probability is approximately 0.1587, and for z = -2.0, it is about 0.0228. Therefore, the area between these two z-scores is approximately 0.1587 - 0.0228 = 0.1359, or 13.59%.
What is the value of z if the area between -z and z is 0.777?
To find the value of ( z ) such that the area between (-z) and (z) under the standard normal distribution curve is 0.777, we need to determine the corresponding cumulative probability. The area between (-z) and (z) represents the central portion of the distribution, so we can express this as: ( P(-z < X < z) = 0.777 ). This means that ( P(X < z) - P(X < -z) = 0.777 ). Since the distribution is symmetric, ( P(X < -z) = 1 - P(X < z) ), leading to ( 2P(X < z) - 1 = 0.777 ) or ( P(X < z) = 0.8885 ). Using a standard normal distribution table or calculator, we find that ( z \approx 1.175 ).
What is P(0 z 2.53)?
P(0 < z < 2.53) refers to the probability that a standard normal random variable (z) falls between 0 and 2.53. To find this probability, you would typically look up the z-scores in a standard normal distribution table or use a calculator. The cumulative probability for z = 2.53 is approximately 0.994, and for z = 0, it is 0.5. Therefore, P(0 < z < 2.53) is approximately 0.994 - 0.5 = 0.494.
Find the z-score for which 8 percent of the distribution's area lies between -z and z?
To find the z-score where 8% of the distribution's area lies between -z and z, we first recognize that this means 4% (or 0.04) lies in each tail of the normal distribution. Therefore, we need to find the z-score that corresponds to the cumulative area of 0.04 in the left tail. Using standard normal distribution tables or a calculator, we find that the z-score for 0.04 is approximately -1.75. Thus, the positive z-score is approximately 1.75, meaning z ≈ 1.75.
What is the area under the normal distribution curve between z 1.52 and z2.43?
To find the area under the normal distribution curve between z = 1.52 and z = 2.43, you can look up the z-scores in a standard normal distribution table or use a calculator. The area to the left of z = 1.52 is approximately 0.9357, and the area to the left of z = 2.43 is approximately 0.9925. Subtracting these values gives an area of approximately 0.9925 - 0.9357 = 0.0568. Thus, the area between z = 1.52 and z = 2.43 is about 0.0568.
