There's no way to tell exactly, but if you limit yourself to integers, the dimensions will total half the perimeter, like
1 x 23
2 x 22
3 x 21 and so on.
If it was a square, it would be 12 x 12.
Length = 16 feetWidth = 8 feetDistance around the perimeter =Length + width + length + width = 16 + 8 + 16 + 8 = 48 feet.
28 inches
The rectangle is of length 16ft and width 8ft.The CalculationA rectangle's perimeter is made from two lengths and two widths. Therefore, p=2l+2w.2l+2w=48. l+w=24l=2w. 3w=24. w=8, l=16.
Perimeter=4l=4×l ,or,4×12=48
7 x 17
Length = 16 feetWidth = 8 feetDistance around the perimeter =Length + width + length + width = 16 + 8 + 16 + 8 = 48 feet.
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
The maximum area is attained when the rectangle is, in fact, a square. Since the perimeter = 48 feet, the maximum length for a square = 48/4 = 12 feet. So max area = 122 = 144 square feet.
perimeter = (2*length) + (2*width) length = 2*width so perimeter = (2*2*width) + 2*width = 6*width perimeter = 48 so you can figure out the width and length
28 inches
112 inches
The rectangle is of length 16ft and width 8ft.The CalculationA rectangle's perimeter is made from two lengths and two widths. Therefore, p=2l+2w.2l+2w=48. l+w=24l=2w. 3w=24. w=8, l=16.
Perimeter=4l=4×l ,or,4×12=48
48-ft
7 x 17
Perimeter = 2*(Length + Width) = 2*(15+9) = 48 feet.
The width is 6 feet. The length is 8 feet.