By Pythagoras, diagonal = sqrt(32 + 22) = sqrt(9 + 4) = sqrt(13) = 3.606 cm (approx)
18 square cm
The side of a square is is cube root of 2cm. Find the length of the diagonals.
30cm
12cm
The perimeter of a rectangle is calculated by adding together all four sides. In this case, the rectangle has a length of 6cm and a width of 2cm. To find the perimeter, you would add the length (6cm) + width (2cm) + length (6cm) + width (2cm) = 16cm. Therefore, the perimeter of a rectangle with sides measuring 6cm by 2cm is 16cm.
I am not sure what the point is for you to give us the dimensions of a rectangle and then ask what one of those dimensions is. Perhaps you are not sure whether the shorter or the longer of the two dimensions would be considered the length, and which the width. I would say that a rectangle measuring 2cm x 5cm is 2cm wide and 5cm long.
You question is does not make sense. The base is a straight line , NOT an area. You either want the Area of the rectangle or the Length of the base. The Area of a rectangle is found by multiplying the base (length) to the width(height). A = lW (or BH) Algebraically rearrange to find the base length B = A/H ( That is area divided by height).
4 and 26 hope this helps you :)
To find the area of a rectangle, you multiply its length by its width. In this case, the length is 6 cm and the width is 2 cm. Therefore, the area of the rectangle is 6 cm x 2 cm = 12 square cm.
The area of a rectangle is calculated by multiplying its length by its width. For a rectangle with a length of 4 cm and a width of 2 cm, the area would be 4 cm × 2 cm = 8 cm².
area of rectangle = l* b = 5 * 2=10 cm^ 2
The area of a rectangle is given by the formula: length x width. So, for the textbook, the area would be 5cm x 2cm = 10 square cm.