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I am not sure what the point is for you to give us the dimensions of a rectangle and then ask what one of those dimensions is. Perhaps you are not sure whether the shorter or the longer of the two dimensions would be considered the length, and which the width. I would say that a rectangle measuring 2cm x 5cm is 2cm wide and 5cm long.
What else can I help you with?
How do you find the area of a cylander?
-- Slice it down one side and flatten it out. -- Now you have a rectangle. You only have to find the area of a rectangle. -- The area of a rectangle is (length) times (width). -- The length of the rectangle used to be the length of the cylinder. -- The width of the rectangle used to be the circumference of the cylinder's round ends, while it was still rolled up.
Does length go up an down or straight across?
Straight across
How do you get the outer surface area of a cylinder?
Think of slitting the cylinder down one side, then unroll it and lay it down flat. What you have then is a rectangle. The area of the rectangle is: (length x width). The length of the rectangle used to be the length of the cylinder, and the width of the rectangle used to be the circumference of the circle at the end of the cylinder, which is (pi) x (diameter of the cylinder), or (pi) x (double the radius of the cylinder). We're sure you can do it now.
How do you use the line of symmetry to find the equal lengths in a rectangle?
In a rectangle, the line of symmetry runs vertically down the center or horizontally across the middle, dividing the shape into two equal halves. To find equal lengths, measure the distance from the line of symmetry to one side of the rectangle; this distance will be the same on the opposite side. Additionally, since opposite sides of a rectangle are equal, knowing one length allows you to conclude that the corresponding length on the other side is the same. Thus, the line of symmetry helps visually confirm and measure these equal lengths.
What is the width of a rectangle with length 5.5 cm and area of 48400?
8800cm = 88mAssume the area is 48,400 cm2.Since area = length x width, The width is the area divide by the length.48400/5.5 = 8800A rectangle 5.5cm by 88m would resemble the chalk line down the edge of a football field.
Is length across or down?
it goes up and down not across
What does the Olds Intrique coolant light look like?
It looks like a rectangle with squiggles going across the middle of it, with an arrow pointing down.
How do you work out the area of 2D shapes?
u times the length by the width. ( that means times the line going across buy the line going down)
How do you find the area of a cylander?
-- Slice it down one side and flatten it out. -- Now you have a rectangle. You only have to find the area of a rectangle. -- The area of a rectangle is (length) times (width). -- The length of the rectangle used to be the length of the cylinder. -- The width of the rectangle used to be the circumference of the cylinder's round ends, while it was still rolled up.
Does length go up an down or straight across?
Straight across
How do you get the outer surface area of a cylinder?
Think of slitting the cylinder down one side, then unroll it and lay it down flat. What you have then is a rectangle. The area of the rectangle is: (length x width). The length of the rectangle used to be the length of the cylinder, and the width of the rectangle used to be the circumference of the circle at the end of the cylinder, which is (pi) x (diameter of the cylinder), or (pi) x (double the radius of the cylinder). We're sure you can do it now.
How to make grade iii understand length and width?
the length is down and the width is across.
How does electronegative change going down and across the table?
Electronegativity increases across (left to right) the periodic table and decreases on going down.
What general trend in electronegativity do you note going down a group across a period?
going down a group, electronegativity decreases going across a period, electronegativity increases
What is the width of a rectangle with length 5.5 cm and area of 48400?
8800cm = 88mAssume the area is 48,400 cm2.Since area = length x width, The width is the area divide by the length.48400/5.5 = 8800A rectangle 5.5cm by 88m would resemble the chalk line down the edge of a football field.
What do you call it when you have a word going down with sentences going across?
you call that an acrostic poem/sentences.
How do you find the area of a kite with long line down is 6 and the line going across is 5?
1/2 the length x the width.
