Length 1 and Width 17 Length 2 and Width 16 Length 3 and Width 15 Length 4 and Width 14 etc..... get the picture
Depends on what make and model
YOu add a # to the width and then you subtract the same # from the length! If you want to go all the way and make the area as big as possible, then you want to make the length and width both 1/4 of the perimeter.
You CAN'T calculate the perimeter of a rectangle, knowing only its diagonal. You do need some additional information about the rectangle - such as its width, or its length, or perhaps the length/width ratio.
Make sure both length and width are measured in meters and multiply. The unit with be the area in square meters. The length and width alone can't be square measurements because they are one dimentional
The area of a rectangle is its Length times its Width. For the question, we first need to make sure that the Length and Width share the same units: Length = 2m Width = 16cm = 0.16m Now we can safely calculate the area: Area = Length x Width = 2 x 0.16 = 0.32 square meters
Take its length and multiply by its width. For example:- Length-30cm,Width-19cm Area=length x width =30x19(cm) =570 units2. Answer=The area of the rectangle is 570 units2. Note: Make sure to use the same units for length and width. The result is measured in units².
The area of the rectangle is the length multiplied by the width. Also, the length is 2 feet longer than the width. Next, make the length represented by the variable l and the width represented by the variable w to make a few equations. lw=48 l=w+2 also written as l-w=2 After taking a variable away and then substituting the known variable back in, you get the length of the retangle as 8 and the width as 6.
The question does not make any sense.
Area = Length * Width Make both X X = width X + 2 = Length X(X+2) = 80 X^2 + 2X = 80 X^2 + 2X -80 = 0 Easy factoring (X-8)(X+10) no negative lengths or widths, so Length = 10 yards Width = 8 yards
You cant, you can make it longer in width however. or you could try aplying time
All four sides must be equal so you would have to either increase the width until it equals the length, or decrease the length until it equals the width.