It is: 58/10 = 5.8 units of length
10*length of a side.
130 What! How about one tenth of its perimeter?
A decagon has 10 equal sides, so if the perimeter is 120 cm each side must be 12 cm
If the hexagon isn't regular, then the formula is: Perimeter = (side-1 length)+(side-2 length)+(side-3 length)+(side-4 length)+(side 5 length)+(side-6 length) If the hexagon is regular, then the formula is: Perimeter = 6 x (length of any side)
The perimeter of a regular pentagon is five times the side length.
10*length of a side.
130 What! How about one tenth of its perimeter?
A decagon has 10 sides. If it is a regular decagon, all of the sides are the same length. Each side would be 0.8 yards or 2.4 feet in length.
8 yds * * * * * That is simply nonsense. In a regular decagon, each of the 10 sides is of the same length. So the length of each side is 22/10 = 2.2 feet.
A decagon has 10 sides, therefore, with side length 13.5 centimetres, the perimeter would be 13.5 x 10 = 135 centimetres.
find the perimeter of a decagon if all off the sides equal 4mi.
100 cm
A decagon has 10 equal sides, so if the perimeter is 120 cm each side must be 12 cm
The perimeter of a regular hexagon with a side length of 6.8mm is 40.8mm
If the hexagon isn't regular, then the formula is: Perimeter = (side-1 length)+(side-2 length)+(side-3 length)+(side-4 length)+(side 5 length)+(side-6 length) If the hexagon is regular, then the formula is: Perimeter = 6 x (length of any side)
Assuming a regular ten-sided shape, of which every side is the same length, each side will be 114/10 = 11.4 centimetres.
The perimeter of a regular pentagon is five times the side length.