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x² + y² - 10 = 49

→ x² + y² = 59

= (x - 0)² + (y - 0)² = (√59)²

→ circle has centre (0, 0) - the origin - and radius √59

The point (7, -2) has a distance from the centre of the circle of:

√((7 - 0)² + (-2 - 0)²) = √(7² + (-2)²) = √(49 + 4) = √53 < √59

Which means that the point is INSIDE the circle and all lines drawn from it to a point on the circumference will NOT be a tangent - the lines will CROSS the circumference, not touch it.

Thus there is no solution to the problem as posed.

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If the equation for the circle is wrong (which is most likely given as how it was stated) please re-submit your question with the correct equation for the circle.

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Q: What is the length of a tangent line from the point 7 -2 to a point when it touches the circle x2 plus y2 -10 equals 49?
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