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What is the length of the tangent line from the point 9 0 to a point where it touches the circle of x2 plus 8x plus y2 -9 equals 0?
Equation of circle: x^2 +8x +y^2 -9 = 0
Completing the square: (x+4)^2 +y^2 = 25
Radius of circle: 5
Center of circle: (-4, 0)
Distance from (9, 0) to (-4, 0) is 13 which is the hypotenuse of a right angle triangle
Using Pythagoras' theorem: 13^2 -5^2 = 144 and its square root is 12
Therefore length of tangent line is: 12 units
Note that a tangent line always meets the radius of a circle at right angles.
What else can I help you with?
What is the length of the tangent line from the point 0 0 to a point where it touches the circle x2 plus y2 plus 4x -6y plus 10 equals 0 on the Cartesian plane?
Equation of the circle: x^2 +y^2 +4x -6y +10 = 0 Completing the squares: (x+2)^2 +(y-3)^2 = 3 Radius of the circle: square root of 3 Center of circle: (-2, 3) Distance from (0, 0) to (-2, 5) = sq rt of 13 which is the hypotenuse of right triangle. Using Pythagoras' theorem : distance squared - radius squared = 10 Therefore length of tangent line is the square root of 10 Note that the tangent of a circle meets its radius at right angles.
Does a trigonometry tangent relate to a circle's tangent?
A circle's tangent is exactly the same as a triangle's tangent. If you look at a circle, you can make the radius the hypotenuse. Then make a vertical line from the point, and a horizontal line from the center. If you look, you have a triangle made inside the circle. This is why angles can be measured in radians, a unit that is derived from the circumference of a circle.-------------------------------------------------------------------------------------------By doing a little calculus, we find that the slope of the equation of a circle-the slope of the tangent line-is given by the tangent of an angle.AnswerEverything written above is correct, but doesn't have anything to do with tangents (in the circle sense of the word). Suppose you're given an angle theta. Draw a circle together with two radii, one horizontal and the other at an angle theta from the first one. (So far, this is the same as above.) Now draw the tangent to the circle at X, the point where the non-horizontal radius meets the circumference. Let Y be the point where this tangent meets the horizontal line through the centre. Then, assuming the radius is 1, tan(theta) is the distance XY, which is the length of part of the tangent.
What is the length of the circle radius if the circle is x2 plus y2 equals 1?
The center of the circle is at (0, 0) and its radius is the square root of 1 which is 1
Find the length of the arc on a circle of radius r equals 16 inches intercepted by a central angle 0 theta equals 60 degrees?
The length of an arc on a circle of radius 16, with an arc angle of 60 degrees is about 16.8.The circumference of the circle is 2 pi r, or about 100.5. 60 degrees of a circle is one sixth of the circle, so the arc is one sixth of 100.5, or 16.8.
What is C equals R times 2 times Pi?
The circumference of a circle. This is the total amount of length around the circle. C= Circumference R= radius of the circle Pi=3.14159
What is tangent line?
tan A = (sin A) / (cos A) tan (A)= opposite side length/adjacent side length A is an angle measurement; amount of degrees or radians. If a line is tangent to a curve, it only touches the curve at one point. looks like )| but the line is touching the curve. In a circle, the tangent line touches the circle at one point and is perpinducular to the circle's radius if it is touching that same point.
What is the length of the tangent line from the coordinate of 9 0 to a point where it touches the circle of x2 plus 8x plus y2 -9 equals 0?
Circle equation: x^2 +8x +y^2 -9 = 0 Completing the square: (x+4)^2 +y^2 = 25 Center of circle: (-4, 0) Radius of circle: 5 Distance from (-4, 0) to (9, 0) = 13 which will be the hypotenuse of a right triangle Length of tangent line using Pythagoras; theorem: 13^2 -5^2 = 144 Therefore length of tangent line is the square root of 144 = 12 units
If a circle of radius 2 is externally tangent to a circle of radius 8 what is the length of their common tangent?
the length of thr direct common tangent will be 2*{1/2 power of (r1*r2)} the answer will be 8 units in this case...
Theorem Length of tangent drawn from external point to a circle are equal?
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What is the length of the tangent line from the point 0 0 to a point where it touches the circle x2 plus y2 plus 4x -6y plus 10 equals 0 on the Cartesian plane?
Equation of the circle: x^2 +y^2 +4x -6y +10 = 0 Completing the squares: (x+2)^2 +(y-3)^2 = 3 Radius of the circle: square root of 3 Center of circle: (-2, 3) Distance from (0, 0) to (-2, 5) = sq rt of 13 which is the hypotenuse of right triangle. Using Pythagoras' theorem : distance squared - radius squared = 10 Therefore length of tangent line is the square root of 10 Note that the tangent of a circle meets its radius at right angles.
What is the length of the tangent line from the point 7 -2 to a point where it touches the circle of x2 plus y2 -10y -24 equals 0 on the Cartesian plane?
Equation of circle: x^2 +y^2 -10y -24 = 0 Completing the square: x^2 +(y-5)^2 = 49 Center of circle: (0, 5) Radius of circle: 7 Distance from (7, -2) to (0, 5) is 7*square root of 2 is hypotenuse of right triangle Using Pythagoras theorem: hypotenuse squared minus radius square = 49 Length of tangent line is the square root of 49 which is 7
What theorems are there for concentric circles?
*If two pair of tangent of inner circle making angles on the circumference of outer circle then the angles so formed are equal . *Any two tangent of inner circle within the outer circle's circumference are equal in length .
What is the length of the tangent line from the point 8 2 to a point where it touches the circle of x2 plus y2 -4x -8y -5 equals 0 on the Cartesian plane?
The distance from (8, 2) to the center of the circle forms the hypotenuse of a right angle triangle with the circle's radius meeting the tangent line at right angles and so:- Equation of the circle: x^2 +y^2 -4x -8y -5 = 0 Completing the squares: (x-2)^2 +(y-4)^2 = 25 Center of circle: (2, 4) Radius of circle: 5 Distance from (8, 2) to (2, 4): 2 times square root of 10 Using Pythagoras' theorem: distance squared minus radius squared = 15 Therefore length of the tangent line is the square root of 15
What is the length of the tangent line from the point 9 0 to the circle x2 plus 8x plus y2 -9 equals 0?
Equation of circle: x^2 +8x +y^2 -9 = 0 Completing the square: (x+4)^2 +y^2 = 25 Radius of circle: 5 Center of circle: (-4, 0) Distance from (9, 0) to (-4, 0) = 13 which is the hypotenuse of a right angle triangle Using Pythagoras: 13^2 -5^2 = 144 and its square root is 12 Therefore the length of the tangent line is 12 units Note that the tangent line of a circle meets the radius of the circle at right angles
What is the length of a chord of the circle x2 plus y2 equals 72 which is tangent to the circle x2 plus y2 equals 18?
The circles are concentric with centre (0,0). The radius of the outer circle is sqrt(72), that of the inner circle is sqrt(18). By Pythagoras, the length of the semichord is sqrt(72 - 18) = sqrt(54) units. Therefore the chord is 2*sqrt(54) = 6*sqrt(6) = 14.679 units (approx).
A tangent segment and a secant segment are drawn to a circle from a point outside the circle. The length of the tangent segment is 15 inches. The external segment of the secant segment measures 5 inches. What is the measure of the internal secant segment?
Course Hero Question A tangent segment and a secant segment are drawn to a circle from a point outside the circle. The length of the tangent segment is 15 inches. The... Answer · 0 votes Length of interior part of secant = 40 inches Please see attached image for diagram with work shown Image transcriptions The tangent—secant theorem states that if a tangent and a secant are drawn from the same external point, the length of the tangent squared is equal to the external part of the secant multiplied by the whole segment. 15_ Let x = the length of the inner segment of the secant II'I ' Length whole secant = length interior of secant + length exterior of secant 5 in = x + 5 (tangent? = (length exterior) * (length whole secant) (15)2 = (5) * (x + 5) 225 = 5x + 25 200: 5x 40:): Measure of internal segment = 40 inches More
How do you find the length of a radius drawn from the center of the circle to a tangent?
It is the same length from the centre to any point on the circumference so just measure it
