if you start at one point and then go 44ft and then make 90 feet a right angle with it then at the end ofthe 94foot length make the 50foot length 90 degrees with the 94 foot length. this should made an open rectangle with one end slightly longer than the other. on the two ends attach a line and this line should be slanted. take 50-44 and get 6 ft as the remaining horizontal distance. and 90ft is your vertical distance. sovle like a pythagorean theorem.
942 + 62 = 8136
take square root of 8136
the length of your distance is 94.2ft
It depends on what geometric shape whose perimiter is 44ft is used. A square would have an area of 480 sq ft (length x width), a rectangle 21 feet by 1 foot would have an area of 21 sq ft (length x width), and a circle would have an area of 154.0619 (area of a circle = perimeter squared divided by 4 pi).
You can't. The area doesn't tell you the dimensions. There are an infinite number of shapes and different dimensions that all have the same area.Here are a few rectangles that all enclose 1,111 square feet:2ft 9in x 404ft5ft 6in x 202ft11ft x 101ft22ft x 50ft 6in25ft 3in x 44ft
12' x 10'
44ft x 32inches equals 10.9 square meters.
44ft lbs. +90 deg.
Regulated Draft is 40ft FW from Sabine Pass to the Port of Beaumont. Actual depth is 42-44ft.
44ft/lbs + 90 degrees. So torque the new head bolts to 44 ft/lbs then turn an additional 90degrees.
There is currently no difference in dimensions of a badminton court between a singles or doubles game of badminton. The court is rectangular and divided into halves by a net. Courts are almost always marked for both singles and doubles play, although the laws permit a court to be marked for singles only. The doubles court is wider than the singles court, but both are the same length. The exception, which often causes confusion to newer players is the doubles court has a shorter serve-length dimension. The full width of the court is 6.1 metres (20 ft), and in singles this width is reduced to 5.18 metres (17 ft). The full length of the court is 13.4 metres (44 ft). The service courts are marked by a centre line dividing the width of the court, by a short service line at a distance of 1.98 metres (6.5 ft) from the net, and by the outer side and back boundaries. In doubles, the service court is also marked by a long service line, which is 0.78 metres (2 ft 6 inch) from the back boundary. The net is 1.55 metres (5 ft 1 inch) high at the edges and 1.524 metres (5 ft) high in the centre. The net posts are placed over the doubles side lines, even when singles is played. There is no mention in the Laws of badminton, of a minimum height for the ceiling above the court. Nonetheless, a badminton court will not be suitable if the ceiling is likely to be hit on a high serve.
15 ft lbs at a time until attaining 44ft lbs. Then turn all bolts in sequence 95% of a full 360 rotation
15 fp then 75 degrees This is why this site is really lame, this guy/gal is dangerous. the correct value is 44ft/lbs then 90 degree turn +- 5 degrees
There are 1,341.12 centimeters in 44 ft. To get this, multiply 2.54 cm by 12, since there are 2.54 cm in 1 in. You would get 30.48 centimeters. Now multiply that by 44, since 12 in. equals 1 foot, and you get 1,341.12 centimeters.
The court is rectangular in shape and divided into two half using a net.Width: 6.1metres (20ft) [For singles it is 5.18metres (17ft)]Length:13.4metres (44ft)Net Height: 1.55 metres (5 ft 1 inch) at the edge and 1.524 (5 ft) at the center.This answer is courtesy Sports365.in.