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What is the length of the diagonal of a rectangle in cm whose height is greater than its width by 13.5 mm and has an area of 2187 square mm showing key stages of work?
Wiki User
∙ 10y ago
1 13.5 mm = 1.35 cm and 2187 sq mm = 21.87 sq cm
2 Let the height be x+1.35 and the width be x
3 (x+1.35)*x = 21.87
4 x2+1.35x-21.87 = 0
5 Solving the quadratic equation gives x a positive value of 4.05
6 Therefore: width = 4.05 cm and height = 5.4 cm
7 Using Pythagoras: diagonal = 6.75 cm
8 Check: 4.05*5.4 = 21.87 square cm = 2187 square mm
Wiki User
∙ 10y ago
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