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Use the Pythagorean Theorem (a2 + b2 = c2, where a and b are the legs and c is the hypotenuse) and then you will know the base of the rectangle (which would be a or b, depending on which you use). Then you can multiply the base and height to find the area of the rectangle!
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What is the area of a rectangle with a diagonal of 39 and a height of 15?
Using Pythagoras its base works out as 36 and so 36*15 = 540 square units
The area of rectangle?
Rectangle area = (rectangle width) x (rectangle height)
What is the Formula for area of rectangle using diagonal length?
Let a, b, and c be the width, height, and diagonal of the rectangle.Pythagorus' theorem applies to the rectangle as follows: a^2 + b^2 = c^2substitute for 'a' from Pythagoruss theroem: a = sqrt(c^2 - b^2)Therefore, Area = a * b = b * sqrt(c^2 - b^2)
Which formula for the area of a parallogram is similar to a rectangle circle triangle ellipse or trapezoid?
Rectangle Area of parallelogram = Base * Height Area of rectangle = Base * Height
The diagonal of the rectangle is 26m and its perimeter is 68m. Find its area?
240 sq m
What is the area of a rectangle that has a diagonal of 5 and a height of 3?
15 units2
Can you explain why the area of a triangle is 1 half base height while the area rectangle or a parallelogram is expressed as base height?
If you draw a diagonal in a rectangle you get two equal triangles, each half the area of the rectangle. Area of rectangle is base x height, so half of that is ½ x base x height. QED
What is the area of a rectangle with a diagonal of 39 and a height of 15?
Using Pythagoras its base works out as 36 and so 36*15 = 540 square units
Can you find the area of a rectangle if the problem doesn't show you the base and height?
The one alternative to find the area of a rectangle is when you are given the length of one diagonal and its slope.
If the diagonal and the area of a rectangle are 25 m and 168 m2 what is the length of the rectangle?
If the diagonal is 25m and the area is 168m2 then the longest edge of the rectangle will be 24m.
How can you find the area of a rectangle if the given is the perimeter and the diagonal?
First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
How do you find the length of rectangle diagonally by using the area given?
You can't. Suppose for instance your rectangle is 1xA, then the diagonal length is sqrt(1+A**2). But if your rectangle is sqrt(A)xsqrt(A) then your diagonal length is sqrt(2*A). The only thing one can say for sure is that the diagonal length is at least sqrt(2*A).
The area of rectangle?
Rectangle area = (rectangle width) x (rectangle height)
What is the Formula for area of rectangle using diagonal length?
Let a, b, and c be the width, height, and diagonal of the rectangle.Pythagorus' theorem applies to the rectangle as follows: a^2 + b^2 = c^2substitute for 'a' from Pythagoruss theroem: a = sqrt(c^2 - b^2)Therefore, Area = a * b = b * sqrt(c^2 - b^2)
How do you find the area of a rectangle with the diagonal of 13 and a width of 5?
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
How do you find the area of a rectangle from diagonal and 1 angle?
The diagonal multiplied by sin(angle) gives one side of the rectangle and the diagonal times cos(theta) gives the other. So the area is (diagonal)2 x cos(theta) x sin(theta).
How can you show that the area of a triangle half the area of the rectangle with the same base and height?
Draw a diagonal line across the rectangle. The resulting two right triangles will each have identical areas half that of the rectangle. The area of the rectangle is its height x base, and the area of each of the two triangles is 1/2 of its height x base.
