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In order to find the hypotenuse the height and base must be found first so let the height be (x+4) and the base be x:

1/2*height*base = area

1/2*(x+4)*x = 96 cm2

Multiply both sides by 2:

(x+4)*x = 192

Multiply out the brackets and subtract 192 from both sides hence forming a quadratic equation:

x2+4x-192 = 0

Using the quadratic equation formula gives x a positive value of 12.

So: length = 16 cm and width = 12 cm

Use Pythagoras' Theorem to find the hypotenuse:

162+122 = 400 and the square root of this is 20

Therefore the length of the hypotenuse is 20 cm

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Q: What is the length of the hypotenuse of a right angle triangle when its height is 4 cm greater than its base and has an area of 96 square cm showing all details of your work?
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Can you work out the length of the hypotenuse of a right angle triangle with sides VIII and VI inches showing all your workings in roman numerals?

Pythagoras' Theorem states that for any right angle triangle the height squared plus the base squared is equal to the square of the hypotenuse. In other words, after finding the square of the hypotenuse, square root your answer to find its length. Hence: (8*8)+(6*6)=64+36=100. The square root of 100=10. Therefore the length of the hypotenuse is 10 inches. In Roman numerals: (VIII*VIII)+(VI*VI)=LXIIII+XXXVI=C. The square root of C=X. Therefore the length of the hypotenuse is X inches. David Gambell, Merseyside, England.


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Augustus Pythagoras: let the equal sides be 1 unit. The square of the third side, which is the hypotenuse, is equal to the sum of the squares of the other two sides, in this case 12 and 12, a total of 2. The hypotenuse is therefore equal to the square root of two.


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Presumably it's a right angle triangle so use Pythagoras' theorem and let the hypotenuse be (x+21.2) the height be (x+18.55) and the base be x:- (x+21.2)2-(x+18.55)2 = x2 If: (x2+42.4x+449.44)-(x2+37.1x+344.1025) = x2 Then: -x2+5.3x+105.3375 = 0 Solving the above by means of the quadratic equation formula gives x a positive value of 13.25 So the dimensions are: hypotenuse 34.45 cm, height 31.8 and base 13.25 cm Area = 0.5*31.8*13.25 = 210.675 square cm


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First find the length of the base: base = area times 2 divided by height base = 12x2/4 = 6 inches An isosceles triangle can be considered as being two right angled triangles joined together. So by halving the length of the base we can use Pythagoras' Theorem to find the hypotenuse: base2+height2 = hypotenuse2 32+42 = 25 square inches. Square root of 25 = 5 inches Therefore the isosceles triangle has two equal sides of V inches and a base of VI inches.

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Can you work out the length of the hypotenuse of a right angle triangle with sides VIII and VI inches showing all your workings in roman numerals?

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What is the proof for showing that the sides of an isosceles right triangle are in the ratio of one to one to the square root of 2?

Augustus Pythagoras: let the equal sides be 1 unit. The square of the third side, which is the hypotenuse, is equal to the sum of the squares of the other two sides, in this case 12 and 12, a total of 2. The hypotenuse is therefore equal to the square root of two.


What is the area of a triangle when its shortest side is less than the other sides by 18.55 cm and 21.2 cm respectively showing brief details of your work?

Presumably it's a right angle triangle so use Pythagoras' theorem and let the hypotenuse be (x+21.2) the height be (x+18.55) and the base be x:- (x+21.2)2-(x+18.55)2 = x2 If: (x2+42.4x+449.44)-(x2+37.1x+344.1025) = x2 Then: -x2+5.3x+105.3375 = 0 Solving the above by means of the quadratic equation formula gives x a positive value of 13.25 So the dimensions are: hypotenuse 34.45 cm, height 31.8 and base 13.25 cm Area = 0.5*31.8*13.25 = 210.675 square cm


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