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Q: What is the length of the line that spans the parabolas of y equals 4x squared -2x -1 and y equals -2x squared plus 3x plus 5?

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The line x-y = 2 intersects with the curve x^2 -4y^2 = 5 at (2.5, 1/3) and (3, 1) and by using the distance formula its length is 5/6

If you mean: y = 17-3x and y = x^2+2x-7 then the length of the line works out as 11 times square root of 10 or about 34.785 to three decimal places.

In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0

Equations: x2+2x-7 = 17-3x Quadratic equation: x2+5x-24 = 0 Points of intersection: (-8, 41) and (3, 8) Length of line: (-8-3)2+(41-8)2 = 1210 and the square root of this is the length of the line which is about 34.78505426 or to be exact it is 11 times the square root of 10.

The Precambrian spans roughly 4 billion years.

If: y = x^2 +2x -7 and y = 17 -3x Then: x^2 +2x -7 = 17 -3x => x^2 +5x -24 = 0 Solving the equation: x = 3 or x = 8 Points of intersection: (3, 8) and ( -8, 41) Length of line: square root of 1210 which is about 34.785 to three decimal places

If: y = 4x2-2x-1 and y = -2x2+3x+5 Then: 4x2-2x-1 = -2x2+3x+5 So: 6x2-5x-6 = 0 Solving the above quadratic equation: x = -2/3 and x = 3/2 Points by substitution are: (-2/3, 19/9) and (3/2, 5) Length of line is the square root of: (-2/3 -3/2)2+(19/9-5)2 = 65/18

The Brahmaputra River spans through Bangladesh, China and India.Its source is the Chemayungdung Glacier and and the length of it runs for 1,802 miles.

The Brahmaputra River spans through Bangladesh, China and India.Its source is the Chemayungdung Glacier and and the length of it runs for 1,802 miles.

First find the points of intersection of the two equations: 17 - 3x = x2 + 2x - 7 or x2 + 5x - 24 = 0 This has the solutions x = 3 and x = -8 So the coordinates of the two points of intersection are (3,8) and (-8,41). Then, by Pythagoras, the length is sqrt[(3+8)2 + (8-41)2] = sqrt(121 + 1089) = sqrt(1210) = 11 sqrt(10) or 34.785 units (approx).

If: y = x^2+4 and y = 5x+10 Then: x^2+4 = 5x+10 So: x^2-5x-6 = 0 => x = -1 or x = 6 Points of intertsection by substitution: (6, 40 and (-1, 5) Length of line: sq rt of (6--1)^2+(40-5)^2 = 7 times sq rt 26 or 35.693 to 3 d.p.

If: y = 17-3x and y = x^2+2x-7 Then: x^2+2x-7 = 17-3x => x^2+5x-24 = 0 Solving the quadratic equation: x = -8 and x = 3 Points of intersection with the parabola: (-8, 41) and (3, 8) Length of line: square root of [(-8-3)^2+(41-8)^2] = 34.785 to 3 d.p.

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