31/3.1 ie 10
Let's call the length L and the width W. The width is 5 less than half of the length, so W = (1/2)L - 5. The length is 31, so W = (1/2)(31)-5, which is 10.5. So the length is 31 cm and the width is 10.5 cm. The perimeter is 2 lengths and 2 widths, so the perimeter equals 2L + 2W. In this case, it is 2(31) + 2(10.5) which is 83 cm.
the width equals 14 cm. and the length equals 31 cm.
Let the width be 1/2x+2 and the length be x: 2(width+length) = perimeter 2(1/2x+2+x) = 97m x+4+2x = 97 x+2x = 97-4 3x = 93 x = 31 Therefore: length = 31m and width = 17.5m Check: 31+31+17.5+17.5 = 97m
perimeter = length + length + width + width = 2*length + 2*width = 36 length = 5*width 2*(5*width) + 2*width = 36 12*width = 36 width = 3 length = 15
Area = length x width Length = area/width
Length and width
Length / Width
If Length * Width = Area, then Area ÷ width = Length
Area = (length) times (width)Length = (area) divided by (width)Width = (area) divided by (length)
No. It has NO length, NO width, NO height. Only a position.No. It has NO length, NO width, NO height. Only a position.No. It has NO length, NO width, NO height. Only a position.No. It has NO length, NO width, NO height. Only a position.
perimeter = (2*length) + (2*width) length = 2*width so perimeter = (2*2*width) + 2*width = 6*width perimeter = 48 so you can figure out the width and length
It is 2*(Length + Width).