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If the length of a rectangle is 3 cm longer than twice the width and that the perimeter of the rectangle is 90 cm then what is the width and the length?
the width equals 14 cm. and the length equals 31 cm.
The perimeter of a rectangle is 97m The width is 2m more than half the length Find the length and width?
Let the width be 1/2x+2 and the length be x: 2(width+length) = perimeter 2(1/2x+2+x) = 97m x+4+2x = 97 x+2x = 97-4 3x = 93 x = 31 Therefore: length = 31m and width = 17.5m Check: 31+31+17.5+17.5 = 97m
The width of a rectangle is 11 cm mire than the length the area of the rectangle is 1302 cm label which is the length and which is the width show work too please?
W = width of rectangle L = length of rectangle A = area of rectangle W x L = A (L+11) x L = A L squared + 11 L - 1302 = 0 solve for L by quadratic equation or by factoring: (L-31)(L +42) = 0 L = 31 W = L+11 = 42
If 2 different rectangles have the same perimeter why is the area different for each?
Perimeter = 2 x (length + width), area = Length x width. Perimeter is not directly related to area except in the cases of circles and squares. Consider a rectangle of 60 sq cm: the integer possibilities for length and width are numerous: 1 x 60, 2 x 30, 3 x 20, 4 x 15, 5 x 12 and 6 x 10. The respective perimeters are 122 cm, 100 cm, 46 cm, 38 cm, 34 cm and 32 cm. Note that the nearer the shape becomes to a square, the smaller the perimeter. (A square would have a perimeter of a whisker under 31 cm.)
Find the length of a rectangular lot with a perimeter of 140 meters if the length is 8 meters more than the width?
Let the length be x+8 and the width be x: 2(x+8)+2x = 140 2x+16+2x = 140 4x+16 = 140 4x = 140-16 4x = 124 x = 31 Therefore: length = 31+8 = 39 meters
If the length of a rectangle is 3 cm longer than twice the width and that the perimeter of the rectangle is 90 cm then what is the width and the length?
the width equals 14 cm. and the length equals 31 cm.
What is the area and perimeter of a square when l12.3 and w31?
The area of a rectangle of length 12.3 and width 31 is 12.3 X 31 = 381.3, the perimeter of the same rectangle is 2(12.3+31) = 86.6.
How do you find the width and perimeter of a rectangle if the length is 31 cm and the width is 5 less than one half of the length?
Let's call the length L and the width W. The width is 5 less than half of the length, so W = (1/2)L - 5. The length is 31, so W = (1/2)(31)-5, which is 10.5. So the length is 31 cm and the width is 10.5 cm. The perimeter is 2 lengths and 2 widths, so the perimeter equals 2L + 2W. In this case, it is 2(31) + 2(10.5) which is 83 cm.
The perimeter of a rectangle is 97m The width is 2m more than half the length Find the length and width?
Let the width be 1/2x+2 and the length be x: 2(width+length) = perimeter 2(1/2x+2+x) = 97m x+4+2x = 97 x+2x = 97-4 3x = 93 x = 31 Therefore: length = 31m and width = 17.5m Check: 31+31+17.5+17.5 = 97m
A certain rectangle has a width that is half the difference of the length and 6 cm If the Perimeter of the rectangle is 87 cm what is the length and width of the rectangle?
Algebra works great here. Let's use three variables: P for perimeter, L for length and W for width. Then we can rewrite the above in terms of math:W = (1/2)(L - 6)
The width of a rectangle is 11 cm mire than the length the area of the rectangle is 1302 cm label which is the length and which is the width show work too please?
W = width of rectangle L = length of rectangle A = area of rectangle W x L = A (L+11) x L = A L squared + 11 L - 1302 = 0 solve for L by quadratic equation or by factoring: (L-31)(L +42) = 0 L = 31 W = L+11 = 42
The perimeter of a rectangle is 40 feet if the length is 15 feet 6 inches what is the width of the rectangle?
If the length is 15.5 feet then the combined length of the two long sides is 31 feet, this leaves 9 feet, which divided between the two shorter sides means each must be 4.5 feet long or 4 feet 6 inches long if you prefer.
What are the rectangles that have the same perimeter as area?
Perimeter is a length, and a length cannot be the same as an area.Ignoring the units, all rectangles that have the same numerical perimeter as area are those that satisfy:2 x (length + width) = length x widthwhich can be rearranged to give:width = 2 x length/(length - 2)Meaning that given any length over 2, a width can be found to give a rectangle that meets the requirement that its numerical perimeter is the same as its numerical area. (For a length greater than 0 and less than 2, the width would be negative and not possible; similarly for a length less than 0, the length is negative and not possible. When the length is 2, the width is undefined and so not possible. When the length is 0 the width is 0 and it is not a rectangle.)At some stage as the length increases, the length will equal the width and as the length continues to increase the rectangle then given will match the previous rectangles with the length and widths swapped. This occurs when:length = 2 x length/(length - 2)⇒ length x (length - 4) = 0⇒ length = 4.So, as long as the length is greater than or equal 4 it will be the longer side - the length, by convention, is the longer side. Thus all rectangles satisfy:width = 2 x length/(length - 2)with length ≥ 4, will have the numerical value of their perimeter the same as the numerical value of their area.For example:4 cm x 4 cm: perimeter = 16 cm, area = 16 cm25 cm x 31/3 cm: perimeter = 162/3 cm, area = 162/3 cm26 cm x 3 cm: perimeter = 18 cm, area = 18 cm241/2 cm x 33/5 cm: perimeter = 161/5 cm, area = 161/5 cm2etcNote: the first example is a square which is a rectangle with all the sides the same length.
What is the perimeter of 21 inch by 31 inch rectangle?
It is: 21+31+21+31 = 104 inches
The perimeter of a rectangle is 72 what are the length and width?
We don't know. The perimeter doesn't uniquely define the dimensions. It could be: 1 x 35 2 x 34 3 x 33 4 x 32 5 x 31 10 x 26 15 x 21 15.39 x 20.61 . . etc. All of these rectangles have a perimeter of 72.
Tom's yard measure 56 feet in length and 31 feet in width how much fencing does he need to buy to fence in his whole yard?
Perimeter is 56+31+56+31 = 174 feet of fence.
If 2 different rectangles have the same perimeter why is the area different for each?
Perimeter = 2 x (length + width), area = Length x width. Perimeter is not directly related to area except in the cases of circles and squares. Consider a rectangle of 60 sq cm: the integer possibilities for length and width are numerous: 1 x 60, 2 x 30, 3 x 20, 4 x 15, 5 x 12 and 6 x 10. The respective perimeters are 122 cm, 100 cm, 46 cm, 38 cm, 34 cm and 32 cm. Note that the nearer the shape becomes to a square, the smaller the perimeter. (A square would have a perimeter of a whisker under 31 cm.)
