1,000,009
The sum of any two-digit number and the number formed by reversing the digits is always divisible by 11.Why?The algebraic proof is as follows:(10x+y) + (10y+x) = 11x + 11y = 11(x+y)
I am a three digit number. all of my digit is multiples of 2. my hundreds digit is the lowest even number. the sum of my digits is 16. the units digit is the same as the difference between my hundreds and tens digits.
sum
The number whose farthest right significant digit determines it. Whatever place that digit is in is the last significant digit in the sum. For example: 433 + 150 + 3.67 + 8000 = 8586.67, but in sig figs this is only 9000, as the thousands digit is the lowest digit that can be represented.
The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.
The greatest 3-digit number is 999. 9+9+9 = 27 The sum of the greatest 3-digit number is 27.
There is no seven-digit number that has a sum of 5. The smallest seven-digit number is 1,000,000, which already has a sum greater than 5.
54
i am a two digit # my tens digit# is 3 times my ones digit #and the sum of my digit is 12 what am i
101117
99999
"If the units digit and the hundreds digit of the number 513 were reversed..." 315 'find the sum of the original number and the new number." 513+315=828