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The units digit of a two digit number exceeds twice the tens digit by 1. Find the number if the sum of its digits is 10.

Q: The units digit of a two digit number exceeds twice the tens digit by 1 what numbers if the sum of its digit is 10?

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18 and 38

18 and 38

The largest six digit number period is 999999. The largest number meeting your criteria is 998949.

AB If B = x, then A = x + 4 Also, A = 2x -1 So that, 2x - 1 = x + 4 x = 5 B = 5, A = 9 So AB = 95

120 5-digit numbers can be made with the numbers 12345.

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18 and 38

18 and 38

Assuming that the first digit of the 4 digit number cannot be 0, then there are 9 possible digits for the first of the four. Also assuming that each digit does not need to be unique, then the next three digits of the four can have 10 possible for each. That results in 9x10x10x10 = 9000 possible 4 digit numbers. If, however, you can not use the same number twice in completing the 4 digit number, and the first digit cannot be 0, then the result is 9x9x8x7 = 4536 possible 4 digit numbers. If the 4 digit number can start with 0, then there are 10,000 possible 4 digit numbers. If the 4 digit number can start with 0, and you cannot use any number twice, then the result is 10x9x8x7 = 5040 possilbe 4 digit numbers.

None. The sum of one digit can't be twice the size of the digit.

If the number is odd, the last digit is odd. That means the ten's digit must be twice the one's digit. There are only four two-digit numbers where the ten's digit is twice the one's digit: 21, 42, 63, 84. Check which of these satisfy all the clues.

The largest six digit number period is 999999. The largest number meeting your criteria is 998949.

216.

AB If B = x, then A = x + 4 Also, A = 2x -1 So that, 2x - 1 = x + 4 x = 5 B = 5, A = 9 So AB = 95

A proper 2-digit number (which must be smaller than 100) cannot be twice a 10-digit number (which must be larger than 999,999,999).

120 5-digit numbers can be made with the numbers 12345.

216

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