41
It is 41.
41
A number leaves reminder 6 when divided by 10. What is the remainder when the number is divided by 5? Justify your reasoning.
26
5
121.
234568
41
41
forty-one
The integer is 157. 157/3 = 52 remainder 1 157/5 = 31 remainder 2 157/7 = 22 remainder 3
It is LCM(5, 8) + 1 = 41.
6172839
HCF(5, 8) + 1 = 40 + 1 = 41
85
3
It is an integer which, when divided by 2, leaves a remainder of 1.
6. 6 % 5 = 1, where % is the modulo operator (a fancy way of saying that it finds the remainder). If you were instead dividing by 8 and not 5, then the answer would be 9.